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bogdanovich [222]
3 years ago
14

A 10p coin weighs 6.5g. What is the weight of a bag of 10p coins worth £3.50?​

Mathematics
1 answer:
hichkok12 [17]3 years ago
7 0

Answer:

227.5 grams

Step-by-step explanation:

We know that a single 10p coin weights 6.5 g

Now we want to find the weight of a bag of 10p coins, such that the net value is £3.50  (where the weight of the bag is neglected)

The value of a 10p coin is £0.10

So the first thing we need to find, is how many coins there are in the bag.

To find that, we need to find the quotient between the total value and the value of a single coin:

£3.50/£0.10 = 35

So in the bag, we have 35 coins, and each one of them weighs 6.5 grams

Then the total weight is 35 times 6.5 grams:

35*6.5 g= 227.5 grams

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Shamika's grandmother opens an account with a deposit of $5,000 for Shamika as a college savings account. The account pays 5 per
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Answer:

$7500

Step-by-step explanation:

$5000 was deposited

5% annual interest of the $5000 is $250

so in ten years the interest will be 10 ×$250 =$2500

so the total sum that will be in the account is $5000 + $2500 =$7500

7 0
3 years ago
What is the ratio of the intensities of an earthquake PP wave passing through the Earth and detected at two points 19 kmkm and 4
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Answer:

The ratio of the intensities is roughly 6:1.  

Step-by-step explanation:

The intensity I() of an earthquake wave is given by:

I = \frac{P}{4\pi d^{2}}

<em>where P: is the power ans d: is the distance. </em>

Hence, the ratio of the intensities of an earthquake wave passing through the Earth and detected at two points 19 km and 46 km from the source is:

\frac{I_{1}}{I_{2}} = \frac{P/4\pi d_{1}^{2}}{P/4\pi d_{2}^{2}}

<em>where I₁ = P/4πd₁², d₁=19 km, I₁ = P/4πd₂² and d₂=46 km     </em>

\frac{I_{1}}{I_{2}} = \frac{d_{2}^{2}}{d_{1}^{2}}

\frac{I_{1}}{I_{2}} = \frac{46 km^{2}}{19 km^{2}}

\frac{I_{1}}{I_{2}} = 5.9:1

Therefore, the ratio of the intensities is roughly 6:1.  

 

I hope it helps you!    

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3 years ago
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2 years ago
Dennis decided he wanted to go to the carnival. The carnival charges $6.00 for entry and $1.50 for each ride.
myrzilka [38]

We want to create a linear equation to model the given situation.

A) c(r) = $6.00 + $1.50*r

B) 19 rides.

We know that the carnival charges $6.00 for entry plus $1.50 for each ride.

A) With the given information we can see that if you ride for r rides, then the cost equation will be:

c(r) = $6.00 + $1.50*r

Where c(r) is the cost for going to the carnival and doing r rides.

B) If you have $35.00, then we can solve:

c(r) = $35.00 =  $6.00 + $1.50*r

Now we can solve the equation for r.

$35.00 =  $6.00 + $1.50*r

$35.00 -  $6.00 = $1.50*r

$29.00 = $1.50*r

$29.00/$1.50 = r = 19.33

Rounding to the next whole number we get: r = 19

This means that with $35.00, Dennis could go to 19 rides.

If you want to learn more, you can read:

brainly.com/question/13738061

7 0
3 years ago
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