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3 years ago

6

the football team has 4 freshman, 7 sophomores, 10 juniors, and 15 seniors. two players will be chosen at random to participate

in a coin toss. what is the probability that both players chosen will be sophomores?

1 answer:

Anit [1.1K]3 years ago

4 0

This answer would have to be snakskeewhsof ndxjssoaanshew

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Write the equation 0.3x2 + 5x - 7 =0 in general form and then choose the value of "b."

Musya8 [376]

For this case we have that by definition, an equation of the second degree is given by:

$ax ^ 2 + bx + c = 0$

We have the following equation:

$0.3x ^ 2 + 5x-7 = 0$

Then, according to the definition above, we have to:

$a = 0.3\\b = 5\\c = -7$

Thus, b equals 5.

Answer:

$b = 5$

Option C

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2 years ago

Brianna's gross annual salary is $50,676. What is the recommended maximum monthly rent she should pay?

ANEK [815]

Answer with explanation:

Gross Annual Salary of Brianna's= $ 50,676

Monthly Salary of Brianna's

$=\frac{50676}{12}\\\\=4223$ $

We will use $\frac{28}{36}$ rule here,which states that, 28% of monthly income should be used for housing expenditures,and 36 % of monthly income should be used for paying Debt or Debt Purposes.

So, Maximum Monthly Rent that Brianna can pay

= 28 % of 4223

$=\frac{28}{100} \times 4223\\\\ =\frac{118244}{100}\\\\=1182.44$

=$ 1182 (Approx)

Option C: $ 1182

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3 years ago

4 2/5 divided by 1 1/3

Naddik [55]

Answer:

3.3

Step-by-step explanation:

$= > \frac{4 \frac{2}{5} }{1 \frac{1}{3} } \\ \\ = > \frac{ \frac{20 + 2}{5} }{ \frac{3 + 1}{3} } \\ \\ = > \frac{ \frac{22}{5} }{ \frac{4}{3} } \\ \\ = > \frac{22}{5} \times \frac{3}{4} \\ \\ = > \frac{11}{5} \times \frac{3}{2} \\ \\ = > \frac{33}{10} \\ \\ = > 3.3$

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3 years ago

For a standard normal distribution, find the approximate value of P (z greater-than-or-equal-to negative 1. 25). Use the portion

alekssr [168]

Answer:

89%

Step-by-step explanation:

3 0

2 years ago

Can you help me on unmber 2 or 3 Plzz show work

NikAS [45]

Step-by-step explanation:

In,

Question 2 I have already answered,

Q. 3)

<h3><em><u>Given</u></em><em><u> </u></em><em><u>Question</u></em><em><u>:</u></em></h3>

$\frac{ {c}^{2} }{d}$

<em><u>Given</u></em><em><u> </u></em><em><u>values</u></em><em><u>:</u></em><em><u>-</u></em>

c = 6 , d = 3

<em><u>By</u></em><em><u> </u></em><em><u>putting</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>values</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>question</u></em><em><u>, </u></em>

$\frac{ {6}^{2} }{3}$

$= \frac{36}{3}$

= <em><u>12 (Ans)</u></em>

3 0

2 years ago