Question

Help please answer FAST for BRAINIEST!!!! 2x^2 • 8x^-2/ 4x^-2 y^6 Please SIMPLIFY!!!!!

Answer 1

Answer:

$-2y^6 + 16x^3 + -\frac{1}{2}x$

Answer 2

Answer:

$\frac{4x^2}{y^6}$

Step-by-step explanation:

using the rules of exponents

$a^{m}$ × $a^{n}$ = $a^{m+n}$

$\frac{1}{a^{-m} }$ ⇔ $a^{m}$

$a^{0}$ = 1

$\frac{2x^{2}.8x^{-2} }{4x^{-2}.y^{6} }$

= $\frac{16x^{2-2} }{4x^{-2}.y^{6} }$

= $\frac{16x^{0} }{4x^{-2}.y^{6} }$

= $\frac{16}{4x^{-2}.y^{6} }$

= $\frac{4x^2}{y^{6} }$ ( in positive exponent form )