Answer: It might be C
Step-by-step explanation:
Answer:
Option 4: <u>(2x + 16)° + (x)° = 180°</u>
Step-by-step explanation:
See the attached figure.
For a quadrilateral inscribed in a circle
The opposite angles are supplementary.
So, ∠D + ∠B = 180°
From the figure:
∠B = x° and ∠D = (2x+16)°
∴ <u>(2x + 16)° + (x)° = 180°</u>
Answer:
6.7
Step-by-step explanation:
1^2+1^2= root 2
4^2+7^2 = root 65
1/2*root 2 *(root 65/2) = 2.85*2=5.700877+1
=6.7
Answer:
(x+5) (x=3)
(X+5) (x+1)
Step-by-step explanation:
A removeable discontinuity is always found in the denominator of a rational function and is one that can be reduced away with an identical term in the numerator. It is still, however, a problem because it causes the denominator to equal 0 if filled in with the necessary value of x. In my function above, the terms (x + 5) in the numerator and denominator can cancel each other out, leaving a hole in your graph at -5 since x doesn't exist at -5, but the x + 1 doesn't have anything to cancel out with, so this will present as a vertical asymptote in your graph at x = -1, a nonremoveable discontinuity.