Answer:
And replacing we got:
So we are going to expect about 2,85 automobiles for this case.
Step-by-step explanation:
For this case we define the random variable X as "number of automobiles lined up at a Lakeside Olds dealer at opening time (7:30 a.m.)" and we know the distribution for X is given by:
X 1 2 3 4
P(X) 0.05 0.30 0.40 0.25
The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete
For this case we can calculate the epected value with this formula:
And replacing we got:
So we are going to expect about 2,85 automobiles for this case.
Sevenhundred and eighty thousand
Answer: 1) 162.5 2) 261.1 3) 11.5%
<u>Step-by-step explanation:</u>
is: means equals
of: means multiplication
what: means variable
percent: means divide by 100 (move the decimal 2 places to the left
1.
52 is 32% of what number
52 = .32x
<u>÷ .32 </u> <u>÷ .32 </u>
162.5 = x
2.
what number is 70% of 373
x = .70 × 373
x = 261.1
3.
84 is what percent of 732
84 = x ÷ 100 × 732
<u>÷732 </u> <u> ÷ 732 </u>
0.115 = x ÷ 100
<u>×100 </u> <u> × 100 </u>
11.5% = x
Answer:
x > 38° only satisfies the condition.
Step-by-step explanation:
Given triangle ΔNPO, and ∠ PNM is the exterior angle to the interior angle ∠ PNO of the triangle.
So, ∠ PNM = ∠ NPO + ∠ PON
⇒ x = 38° + 39° = 77° {Given that ∠ PNM = 38° and ∠ PON = 39°}
{Since the exterior angle of an interior angle of a triangle is equal to the sum of the other two interior angles}
Hence, x > 38° only satisfies the condition. (Answer)