Answer:
1 1/3 I think
Step-by-step explanation:
Hope I helped :D
Cos(A-B) = cosAcosB + sinAsinB
<span>
cos(</span>π/2 - θ) = cos(π/2)cosθ + sin(π/2)sinθ
π/2 = 90°
cos(π/2) = cos90° = 0. sin(π/2) = sin90° = 1
cos(π/2 - θ) = cos(π/2)cosθ + sin(π/2)sin<span>θ
</span>
= 0*cosθ + 1*sin<span>θ = </span>sin<span>θ
Therefore </span>cos(π/2 - θ) = sin<span>θ
QED </span>
ANSWER
True
EXPLANATION
The given trigonometric equation is:

We take the LHS and simplify to arrive at the RHS.

Collect LCM on the right hand side to get;

This implies that



This identity has been verified .Therefore the correct answer is true.
Answer:
-5
Step-by-step explanation: