Answer:
There are loads, but for example you can find the diagonal from a lamppost the the end of its shadow if you know the height of the post and the length of the shadow.
Hope I helped x
<h3>Answer:</h3>
A) ∠A = ∠A' = 38° and ∠B = ∠B' = 42°
<h3>Explanation:</h3>
The sum of angles in ∆ABC is 180°, so ...
... (2x -2) + (2x +2) + (5x) = 180
... 9x = 180
... x = 20
and the angles of ∆ABC are ∠A = 38°, ∠B = 42°, ∠C = 100°.
___
The sum of angles of ∆A'B'C' is 180°, so ...
... (58 -x) +(3x -18) +(120 -x) = 180
... x +160 = 180
... x = 20
and ∠A' = 38°, ∠B' = 42°, ∠C' = 100°.
_____
The values of angle measures of ∆ABC match those of ∆A'B'C', so we can conclude ...
... A) ∠A = ∠A' = 38° and ∠B = ∠B' = 42°
Answer:
1
Step-by-step explanation:
The absolute value of -3 is 3, so 4-3=1
Your answer is going to be 5x^2+6 because if you simplify and do x(5)x +6 it will equal to 5x^2 + 6
Hope this helped!!
Solve for m:
2 m - 5 - 3 = 10 - m
Subtract like terms. -3 - 5 = -8:
2 m - 8 = 10 - m
Add m to both sides:
2 m + m - 8 = (m - m) + 10
m - m = 0:
2 m + m - 8 = 10
2 m + m = 3 m:
3 m - 8 = 10
Add 8 to both sides:
3 m + (8 - 8) = 8 + 10
8 - 8 = 0:
3 m = 10 + 8
10 + 8 = 18:
3 m = 18
Divide both sides of 3 m = 18 by 3:
(3 m)/3 = 18/3
3/3 = 1:
m = 18/3
The gcd of 18 and 3 is 3, so 18/3 = (3×6)/(3×1) = 3/3×6 = 6:
Answer: m = 6
