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yawa3891 [41]
3 years ago
6

I already know the answer to this problem, I want a explanation on how to get the answer.

Mathematics
2 answers:
DochEvi [55]3 years ago
5 0

\\ \bull\tt\dashrightarrow BC=CE

\\ \bull\tt\dashrightarrow 3x+3y=7x+5y

\\ \bull\tt\dashrightarrow 7x-3x=3y-5y

\\ \bull\tt\dashrightarrow 4x=-2y

\\ \bull\tt\dashrightarrow 2x=-y

\\ \bull\tt\dashrightarrow \dfrac{x}{y}=\dfrac{-1}{2}

Now

\\ \bull\tt\dashrightarrow BE=BC+CE+CD

\\ \bull\tt\dashrightarrow BE=3x+3y+7x+5y+5x-2y+6

\\ \bull\tt\dashrightarrow BE=15x+6y+6

kondor19780726 [428]3 years ago
3 0

Answer:

• BC = CD

(3x + 3y) = (5x - 2y + 6) \\ 5x - 3x =  - 2y - 3y + 6 \\ 2x =  - 5y + 6 \\  \\  \dashrightarrow \: { \tt{x =  \frac{ - 5y + 6}{2} }}

• find BE:

\dashrightarrow \: { \tt{BE = (3x + 3y) + (7x + 5y)}} \\  \\{ \tt{BE = 10x + 8y}}

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