Answer:
always
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given expression is,

To prove this identity we will take the right side of the identity,


![=\frac{1}{2}[\frac{2(1-\text{tan}^2\frac{A}{2})}{2tan\frac{A}{2}}]](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B2%7D%5B%5Cfrac%7B2%281-%5Ctext%7Btan%7D%5E2%5Cfrac%7BA%7D%7B2%7D%29%7D%7B2tan%5Cfrac%7BA%7D%7B2%7D%7D%5D)
[Since
]
= cot A
Hence right side of the equation is equal to the left side of the equation.
Check the picture below.
let's recall that a kite is a quadrilateral, and thus is a polygon with 4 sides
sum of all interior angles in a polygon
180(n - 2) n = number of sides
so for a quadrilateral that'd be 180( 4 - 2 ) = 360, thus
![\bf 3b+70+50+3b=360\implies 6b+120=360\implies 6b=240 \\\\\\ b=\cfrac{240}{6}\implies b=40 \\\\[-0.35em] ~\dotfill\\\\ \overline{XY}=\overline{YZ}\implies 3a-5=a+11\implies 2a-5=11 \\\\\\ 2a=16\implies a=\cfrac{16}{2}\implies a=8](https://tex.z-dn.net/?f=%5Cbf%203b%2B70%2B50%2B3b%3D360%5Cimplies%206b%2B120%3D360%5Cimplies%206b%3D240%20%5C%5C%5C%5C%5C%5C%20b%3D%5Ccfrac%7B240%7D%7B6%7D%5Cimplies%20b%3D40%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Coverline%7BXY%7D%3D%5Coverline%7BYZ%7D%5Cimplies%203a-5%3Da%2B11%5Cimplies%202a-5%3D11%20%5C%5C%5C%5C%5C%5C%202a%3D16%5Cimplies%20a%3D%5Ccfrac%7B16%7D%7B2%7D%5Cimplies%20a%3D8)
Answer:
79
Step-by-step explanation:
60<xy<100
y -2 =x
if it is prime
y cannot be even
so y could be 1,3,5,7,9
x would then be 9,1,3,5,7
but to be between 60 and 100
x must be 7 or 9
so the number must be 79 or 57
57 is not prime so
the number is 79
[First Year]
$600 • 0.04 • 1 year
600 • 0.04 = 24 • 1 = 24
[Second Year]
$600 • 0.045 • 1 year
600 • 0.045 = 27 • 1 = 27
24 + 27 = $51
I believe this is correct and I hope this helps! :)