Answer:
0.09 m/s to the right
Explanation:
The principle of conservation of linear momentum states that in a system of colliding objects, the total momentum before collision is equal to the total momentum after collision, provided there is no external force.
The total momentum, in this question, is the sum of the momentum of the the two marbles. We assume velocity to the right is positive while to the left is negative. Thus, total initial momentum is
After collision, the first marble goes left. Let the velocity of the other marble be v. Then we have
Equating both momenta,
Hence, the larger goes right with a velocity of 0.09 m/s (since it has a positive sign).
If the potential energy of the three-object system is to be a maximum (closest to zero), should object 3 be placed closer to object 1, closer to object 2, or halfway between them?
If the potential energy of the three-object system is to be a maximum (closest to zero), should object 3 be placed closer to object 1, closer to object 2, or halfway between them?
Object 3 should be placed closer to object 1.
Object 3 should be placed on a halfway between object 2 and object 1.
Object 3 should be placed closer to object 2.
Solution
I think that Object 3 should be placed closer to object 2.
Given,
The momentum of the object A before the collision, p₁ =80 Ns
The momentum of the object B before the collision, p₂=-30 Ns
Given that the objects stick together after the collision.
From the law of conservation of momentum, the total momentum of a system should always remain the same. Thus the total momentum of the objects before the collision must be equal to the total momentum of the objects after the collision.
Thus,
Where p is the total momentum of the system at any instant of time.
On substituting the known values,
Therefore the total momentum of the system is 50 Ns
Thus the momentum of the object AB after the collision is 50 Ns
It will have the strongest attraction for a conductor.
Answer: It represents the whole distance traveled. Hope this helps!
Explanation:
