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Aleonysh [2.5K]
2 years ago
14

Which is the Colour of cleanliness

Physics
1 answer:
kirill [66]2 years ago
3 0
White is the cleanliness color
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In the product 6o2 what does the coefficient mean
Lostsunrise [7]

Answer:

a numerical or constant quantity placed before and multiplying the variable in an algebraic expression example ( 4 in 4x y).

Explanation:

Hope this helps! Brainly if so!

3 0
3 years ago
Read 2 more answers
Two particles having charges of 0.440 nC and 11.0 nC are separated by a distance of 1.80 m . 1) At what point along the line con
Harlamova29_29 [7]

Answer:

a) 0.3 m

b) r = 0.45 m

Explanation:

given,

q₁ = 0.44 n C   and q₂ = 11.0 n C

assume the distance be r from q₁  where the electric field is zero.

distance of point from q₂  be equal to 1.8 -r

now,

        E₁ = E₂

\dfrac{K q_2}{(1.8-r)^2} = \dfrac{K q_1}{r^2}

(\dfrac{1.8-r}{r})^2= \dfrac{q_2}{q_1}

\dfrac{1.8-r}{r}= \sqrt{\dfrac{11}{0.44}}

1.8 = 6 r

r = 0.3 m

<h3>b) zero when one charge is negative.</h3>

let us assume  q₁  be negative so, distance from  q₁ be r

from charge q₂ the distance of the point be 1.8 +r

now,

   E₁ = E₂

\dfrac{K q_2}{(1.8+r)^2} = \dfrac{K q_1}{r^2}

(\dfrac{1.8+r}{r})^2= \dfrac{q_2}{q_1}

\dfrac{1.8+r}{r}= \sqrt{\dfrac{11}{0.44}}

1.8 =4 r

r = 0.45 m

4 0
3 years ago
What is the potential energy of a 2500 g object suspended 5 kg above the earth's surface?
Alinara [238K]

Answer:

potential \: energy = mgh \\  = ( \frac{2500}{1000} ) \times 10 \times 5 \\  = 125 \: newtons

if height is 5 m

8 0
3 years ago
Steve and Carl are driving from Scranton to Bridgeport a distance of 180 miles if they're speed averages 60 miles an hour how lo
Anarel [89]
It will take at least 3 hours for them to get to Bridgeport
7 0
3 years ago
If the bat emits a sound at a frequency of 80.2 kHzkHz and hears it reflected at a frequency of 83.5 kHzkHz while traveling at a
solong [7]

To solve this problem we will apply the concepts related to the Doppler Effect. The Doppler effect is the change in the perceived frequency of any wave movement when the emitter, or focus of waves, and the receiver, or observer, move relative to each other.

Mathematically it can be described as

v' = v (\frac{f' ( v - v_{bat}) - f ( v + v_{bat})}{f'(v-v_{bat}) + f ( v + v_{bat})})

Where,

v = Speed of sound

f' = Reflected frequency

f = Emitted Frequency

v_{bat} = Speed of the object

Assuming that the speed of the medium is the speed of sound of 343m / s, we will then have that:

v' = 343 (\frac{(83.5) (343 -3.9) - 80.2(343+3.9)}{83.5(343-3.9) + 80.2(343+4.3)})

v' = 3.0134m/s

8 0
3 years ago
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