Step-by-step explanation:
Since, K is the midpoint of JL.

12w - 27 = -34 + 14
w = 7/12
A -2w+21=-8w+36
w=17/8
B -5/6 w + 2 = -34+14w
w=216/89
C -47-10w=-9w-40-3w
w= 7/2
D 8/7w=13/14w+2
w=28/5
To solve for x we proceed as follows:
from the laws of logarithm, given that:
log_a b=c
then
a^c=b
applying the rationale to our question we shall have:
log_5 x=4
hence
5^4=x
x=625
Answer: x=625
Answer:
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