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timama [110]
3 years ago
10

You can buy 3 t-shirts for $22.50. write and solve a proportion that shows how many t-shirts you could buy with $110

Mathematics
1 answer:
AlexFokin [52]3 years ago
7 0

Answer:

14.6 T-Shirt

Step-by-step explanation:

Well, you divide 22.50 and 3 and you get 7.5.

Once you get 7.5 you divide it by 110 which is 14.6

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What’s the next step to solve the equation -2(n+3)= 9
elena-s [515]

Answer:

-15/2

Step-by-step explanation:

The next step would be to distribute the negative two through the parenthesis,

-2n-6=9

then you add the six, -2n= 15

then you divide by 15 by negative 2 and get -15/2

8 0
3 years ago
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Jonathan is planning a party at the skating rink. The cost for each person attending is 3.50 for sate rental and $5.00 for food.
Zina [86]

He can only invite 35 people

the cost per person = $3.50 + $5.00 = $8.50

dividing $300 by $8.50 determines the amount he can invite

\frac{300}{8.5} = 35.29411...

He can invite 35 people at a cost of $8.50 × 35 = $297.50


7 0
3 years ago
Find out fraction a) 50, (b) 24
vladimir2022 [97]

Step-by-step explanation:

Writing Whole Numbers as Fractions

You can turn any whole number into an equivalent fraction. Just divide it by 1.

#a

\large\purple{\sf{➾50=\frac{50}{1}}}➾50=150

#b

\large\pink{\sf{➾24=\frac{24}{1}}}➾24=124

4 0
2 years ago
Beer shelf life is a problem for brewers and distributors because when beer is stored at room temperature, its flavor deteriorat
Blizzard [7]

Answer:

a) 3.52

b)  0.002399

c)  At α = .05 we reject the null hypothesis.

Step-by-step explanation:

We are given the following information:

Population mean, μ = 6 μg per liter

Sample size, n = 12

Alpha, α = 0.05

6.94, 7.50, 5.87, 7.92, 8.66, 7.78, 7.95, 6.35, 6.16, 6.28, 5.68, 7.02

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{84.11}{12} = 7.009

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.

SS.D = \sqrt{\frac{10.03}{11}} = 0.95

First, we design the null and the alternate hypothesis

H_{0}: \mu \leq 6\\H_A: \mu > 6

We use One-tailed t test to perform this hypothesis.

a) Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n-1}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{7.009 - 6}{\frac{0.95}{\sqrt{11}} } = 3.52

b) P-value for one tailed t-test at 11 degree of freedom and α = 0.05 is 0.002399

c) Since P-value < 0.05

The result is insignificant.

Thus, at α = .05 we reject the null hypothesis.

6 0
3 years ago
Jodi is retiring at the age of 65. When she retires, she estimates that she will need a monthly income for 25 years. If Jodi sta
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the answer is B.$2,154 Not C

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