Answer:
2
Step-by-step explanation:
Answer:
90% confidence interval for the true mean weight of orders is between a lower limit of 103.8645 grams and an upper limit of 116.1355 grams.
Step-by-step explanation:
Confidence interval for true mean weight is given as sample mean +/- margin of error (E)
sample mean = 110 g
sample sd = 14 g
n = 16
degree of freedom = n - 1 = 16 - 1 = 15
confidence level = 90% = 0.9
significance level = 1 - C = 1 - 0.9 = 0.1 = 10%
critical value (t) corresponding to 15 degrees of freedom and 10% significance level is 1.753
E = t × sample sd/√n = 1.753×14/√16 = 6.1355 g
Lower limit of sample mean = sample mean - E = 110 - 6.1355 = 103.8645 g
Upper limit of sample mean = sample mean + E = 110 + 6.1355 = 116.1355 g
90% confidence interval is (103.8645, 116.1355)
The average baggage-related revenue per passenger is $16.30 per passenger.
<h3>Expected value</h3>
Expected value formula: x×p(x)
First step
No passenger=0×.54
No passenger=0
Second step
One checked luggage for first bag=.30×$25
One checked luggage for first bag=$7.50
Third step
Two piece for the first and second bag=.16×($25+$30)
Two piece for the first and second bag=.16×$55
Two piece for the first and second bag=$8.80
Last step
Expected value=$7.50+$8.80
Expected value=$16.30
Therefore the average baggage-related revenue per passenger is $16.30 per passenger.
Learn more about expected value here:brainly.com/question/24305645
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Not a function because of the vertical line test.
Domain is [-2,∞] since the left most point is -2 and the right is unbounded.
Range is (-∞,∞) since it is not bounded in terms of y.
