Question

1. Two cross roads, each of width 10 m, cut at right angles through the centre of a rectangular park of length 750

Answer 1

Answer:

Length of the road parallel to the length of the park= 700m

Width of the road= 10m

Area of the road= l\times b=700m\times10m=7000m^2l×b=700m×10m=7000m

2

Length of the road parallel to the breadth of the park =300m

Width of the road= 10m

Area of this road= l\times b=300m\times10=3000m^2l×b=300m×10=3000m

2

Area of both the roads

=7000m^2+3000m^2-Area\ of\ the\ common\ portion\=7000m

2

+3000m

2

−Area of the common portion

=10000m^2-10m\times10m=10000m

2

−10m×10m

=10000m^2-100m^2=10000m

2

−100m

2

=9900m^2=0.99=9900m

2

=0.99

Area of the park = l\times bl×b

=700m\times300m=210000m^2=700m×300m=210000m

2

Area of the park excluding the roads

=210000m^2-9900m^2=210000m

2

−9900m

2

=200100m^2=20.01=200100m

2

=20.01