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2 years ago

9

Another one bites the dust.

1 answer:

docker41 [41]2 years ago

5 0

Answer:

C

Step-by-step explanation:

PLS GIVE BRAINLIEST

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I believe this is correct

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Answer:

x-3= 4

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In tossing four fair dice, what is the probability of tossing, at most, one 3

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<u>Answer- </u>

In tossing four fair dice, the probability of getting at most one 3 is 0.86.

<u>Solution-</u>

The probability of getting at most one 3 is, either getting zero 3 or only one 3.

$P(A) =The \ probability \ of \ getting \ zero \ 3 =(\frac{5}{6})(\frac{5}{6})(\frac{5}{6})(\frac{5}{6})=\frac{625}{1296} =0.48$ ( ∵ xxxx )

$P(B) = The \ probability \ of \ getting \ only \ one \ 3 =(4)(\frac{1}{6})(\frac{5}{6})(\frac{5}{6})(\frac{5}{6}) = 0.38$ ( ∵ 3xxx, x3xx, xx3x, xxx3 )

P(Atmost one 3) = P(A) + P(B) = 0.48 + 0.38 = 0.86

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2 years ago

Cherries cost $4/lb. Grapes cost $1.50/lb. You can spend no more than $9 on fruit, and you need at least 3 lb in all. Create a g

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