What’s #14&15 and I also need help in #2

I need help asap pls

sp2606 [1]

9514 1404 393

Answer:

a) ∠DAE = 33°; ∠ABD = 57°

b) ∠CEB = 90°

c) ∠ABE = 22°

d) ∠ADE = 15°

Step-by-step explanation:

The diagonals of a rhombus meet at right angles. Each bisects the corner angles at its ends. Adjacent angles are supplementary, opposite angles are congruent, and each diagonal creates two isosceles triangles.

a) ∠DAE = 90° - ∠ADE = 90° -57°

∠DAE = 33°

∠ADE = ∠ABD = 57°

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b) ∠CEB = 90° . . . . . the diagonals meet at right angles

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c) ∠ABE = 44°/2

∠ABE = 22°

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d) ∠ADE = 90° -(1/2)∠DAB = 90° -150°/2

∠ADE = 15°

8 0

3 years ago

What fraction is equivalent to 3/9

Crazy boy [7]

Answer:

the simplified version of 3/9 would be 1/3 but other equivalent fractions of 3/9 would include but are not exclusive to: 2/6, 4/12, 5/15, and etc.

6 0

3 years ago

Read 2 more answers

A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters

In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

$\Rightarrow y=\sqrt{x^2+100}$

Differentiating with respect to t

$\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}$

$\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}$

Since the car driving towards the intersection at 13 m/s.

so, $\frac{dx}{dt}=-13$

$\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)$

Now

$\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)$

$=\frac{24\times (-13)}{\sqrt{676}}$

$=\frac{24\times (-13)}{26}$

= -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0

3 years ago

What are 4 Lemonade war comprehension questions that I can use for Chapter 11-12? (Only answer if you have read the book or are

Bogdan [553]

Who wrote the book lemonade war???

6 0

3 years ago

When Vince does 14 push-ups and 12 sit-ups, it takes a total of 52 seconds. In comparison, he needs 48 seconds to do 12 push-ups

marshall27 [118]

Answer:

it takes 2 seconds to do one situp

it takes 2 seconds to do one pushup

to do 14 pushups, it takes 28 seconds.

to do 12 situps it takes 24 seconds

to do 12 pushups, it takes 24 seconds

BRAINLIEST PLEASE!

hope this helps :)

Step-by-step explanation:

14x + 12y = 52

12x + 12y = 48

^^^ this is an inequality that we can make.

x stands for pushups

y stands for situps

if we subtract the second equation from the first, we get

2x = 4

x = 2

now we can place x in one of the equations to solve for y

12(2)+12y=48

24 + 12y = 48

12y = 24

y = 2

5 0

2 years ago