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Iteru [2.4K]
3 years ago
15

Can someone help me!! ASAP

Mathematics
1 answer:
8_murik_8 [283]3 years ago
6 0

Answer:

It would be 30

Step-by-step explanation:

6*5=30

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kendra biked 10kilometers on monday .she biked twice as many kilometers on tuseday how many total meters did she bike
hram777 [196]

Answer:

10km+10km*2 = 30km

30km*(1000m/1km) = 30000m

In the second equation of the problem, the kilometers from the initial total distance biked is cancelled out by the conversion of kilometers to meters, as seen in the 1000m/1km (or 1000 meters for every 1 kilometer).

Read more on Brainly.com - brainly.com/question/454009#readmore

Step-by-step explanation:

5 0
3 years ago
11. In a swimming race, Yvonne swam 0.18 mile.
marishachu [46]

Answer: D= 0.72

Step-by-step explanation: Because 0.18 times 4 is 0.72 miles.

5 0
3 years ago
Read 2 more answers
4.) The time X (minutes) for a lab assistant to prepare the equipment for a certain experiment is believed to have a uniform dis
Jet001 [13]

Answer:

P(35-2 < X 35+2) = P(33< X< 37)= P(X

And using the cumulative distribution function we got:

P(35-2 < X 35+2) = P(33< X< 37)= P(X

The probability that preparation is within 2 minutes of the mean time is 0.134

Step-by-step explanation:

For this case we define the following random variable X= (minutes) for a lab assistant to prepare the equipment for a certain experiment , and the distribution for X is given by:

X \sim Unif (a= 20, b =50)

The cumulative distribution function is given by:

F(x) = \frac{x-a}{b-a} , a \leq X \leq b

The expected value is given by:

E(X) = \frac{a+b}{2} = \frac{20+50}{2}=35

And we want to find the following probability:

P(35-2 < X 35+2) = P(33< X< 37)

And we can find this probability on this way:

P(35-2 < X 35+2) = P(33< X< 37)= P(X

And using the cumulative distribution function we got:

P(35-2 < X 35+2) = P(33< X< 37)= P(X

The probability that preparation is within 2 minutes of the mean time is 0.134

8 0
3 years ago
Please help! Will give brainiest (if i can) if you answer.
german

Answer:

A

Step-by-step explanation:

5 0
3 years ago
A rectangular box has a square base with an edge length of x cm and a height of h cm. The volume of the box is given by V = x^2h
tiny-mole [99]
Option 4 is correct i.e. <span>The volume of the box is increasing at a rate of 192 cm^3/min.

</span>Given : Volume of the rectangular box  = x²h 
where x is edge and h is height.
The edge and the height are varying with time, therefore, we write,x = x(t)
h = h(t)
dh/dt = -3 and we shall calculate when x = 4, dx/dt = 2 and when h=15 
V = x²h dV/dt = (2x × dx/dt × h) + (x² × dh/dt) dV/dt = 2×4×2×15 + (4)^2 ×(-3) dV/dt = 240 - 48
dV/dt = 192 
Because dV/dt is positive, hence the volume is increasing  
3 0
2 years ago
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