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aliya0001 [1]
3 years ago
7

8×3/4×3/4×8×3/4 Help me please. ​

Mathematics
1 answer:
BaLLatris [955]3 years ago
5 0

Answer:

Answer is 6

Step-by-step explanation:

ok so

8x 3 is 24.

24 is then divided by 12 (4 x 3) to equal 4

4 x 8 x 3 is 96

96 divided by 4 is 24

24 divided by 4 is 6.

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If I had know ill,I would gone to visit you sentence using appropriate conditional classe​
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Answer:

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Step-by-step explanation:

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3 years ago
What does the digit 6 represent in 687,413
Mice21 [21]

Answer:

Hundred Thousand's Place

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3 years ago
Can u help me on this plzz
avanturin [10]
Median: 29
Range: 25
IQR: 14.5

Explanations:

**Median:**
(To find the median, we need to first order all the elements)

Ordered —> 15, 18, 18, 20, 23, 28, 30, 33, 33, 34, 38, 40

(Since there are an even number of elements, we need to add the two elements in the middle and divide by 2)

Median = (28 + 30)/2 = 58/2 = 29

**Range:**

(To find the range, you just have the subtract the smallest one from the largest)

Range = 40 - 15 = 25

**IQR:**

First half of elements —> 15, 18, 18, 20, 23, 28
Second half of elements —> 30, 33, 33, 34, 38, 40

Q1 (Quartile 1) = Median of first half = (18 + 20)/2 = 38/2 = 19
Q3 (Quartile 3) = Median of second half = (33 + 34)/2 = 67/2 = 33.5

IQR = Q3 - Q1 = 33.5 - 19 = 14.5
5 0
3 years ago
The variable z is directly proportional to x, and inversely proportional to y. When x is 4 and y is 13, z has the value 1.230769
Talja [164]

Answer:

Step-by-step explanation:

1.2307692307692.

The first step is to find the proportionality constant.

The formula is

z = kx/y

1.2307692307692 = k * 4/13          Multiply both sides by 13

1.2307692307692 * 13 = 4k

16 = 4*k                                            Divide by 4

k = 16/4

k = 4

=================================

z = k*x/y

x = 9

y = 20

k = 4

z = 4 *9/20

z = 36/20

z = 1.8

7 0
3 years ago
Read 2 more answers
11 NEED HELP ASAP WILL GIVE BRAINLY
fomenos

Answer:

the second answer seems to be the most reassonable

Step-by-step explanation:

3 0
3 years ago
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