Answer:
0,37
Step-by-step explanation:
It will be easier if we noun the events.
A= Cindi's friend comes to England.
B= New England is mostly cloudly.
We are searching the probability of just A doesn´t happen or just A happens but not B.
The probability of A doesn´t happen is one minus the probability of A:

The events A and B are independent for this reason the probability than both occurs is the product of the probability of each event. It means:

The probability of A doesn´t happen or A and B happen is:

Conclusively we have to rest the probability of A doesn´t happen and A and B happen, but A happens and doesn´t happen and the same time is impossible. For this reason, we have the same result.

Then the probability either Cindi's friend does not come to New England, or she does come but it is mostly cloudy is 0.37
Answer:
.2
Step-by-step explanation:
first you add all the pencils up which is 12 next take the probably of taking out one of each pencil .4 for green .2 for black and .6 for yellow next you divide the probably for pulling 1 green bye 2 since your pulling out 2
(9-15)/(-2+4)= -6/2 = -3
-3 is the slope
In its normal way, For example: 214, Write it in the way it is Usually written.
6.0 x 10^-5 I think is the answer