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3 years ago

Write a reclusive rule for the sequence, then give the next two numbers in the sequence 6,1,7,8,15,23

Mathematics

1 answer:

vlabodo [156]3 years ago

5 0

Answer:

aₙ = aₙ₋₁ + aₙ₋₂

where:

a₁ = 6

a₂= 1.

Step-by-step explanation:

We have the sequence:

6, 1, 7, 8, 15, 23, ...

Is easy to see that this sequence works as follows:

You take 2 consecutive numbers, and the next number is the sum of these two.

Then we have:

6 + 1 = 7

1 + 7 = 8

7 + 8 = 15

8 + 15 = 23

Then the n-th term is equal to the sum of the (n - 1) term and the (n - 2) term.

This is written as:

aₙ = aₙ₋₁ + aₙ₋₂

Because in the recursive rule needs two previous terms, we need to specify the two first terms of the sequence.

Then we need to write also:

a₁ = 6

a₂= 1.

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Answer:

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3 years ago

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vesna_86 [32]

Answer:

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3 years ago

Suppose we have 3 cards identical in form except that both sides of the first card are colored red, both sides of the second car

Nikolay [14]

Answer:

probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3

Step-by-step explanation:

First of all;

Let B1 be the event that the card with two red sides is selected

Let B2 be the event that the

card with two black sides is selected

Let B3 be the event that the card with one red side and one black side is

selected

Let A be the event that the upper side of the selected card (when put down on the ground)

is red.

Now, from the question;

P(B3) = ⅓

P(A|B3) = ½

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P(A|B1) = 1

P(B2) = ⅓

P(A|B2)) = 0

(P(B3) = ⅓

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Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;

Thus;

P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]

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3 years ago

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Softa [21]

Answer:

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3 years ago