The quick and easy answer is 3/100
On problems ii, and iii, you just count up the amount of sides on the polygon and add x behind it to create a type of an equation to find the perimeter of that shape that will work as longs as the sides are congruent to each other.
For problems a,b, and c, you just have to calculate what x is. On a, you find what the other side is if one side is 2 and the area is 24. On b you find what the other side could equal if one side is 4 and the area is 16. On c you know what the perimeter is (72) . The longer sides are 2x and the shorter sides are x. SO you divide by the #s and check your work!
If x is equaled to 10 then you will place 10 into 3 and it would look like this 3(10) + 5y= 20 now your next step is to multiply 3•10=30 so 30+5y=20 now all you have to do is 20- (-30)= -10 and then divide by 5 and it’s equal to -10/5= -2
(5,7) (5,4) (7,4) hope that helps
