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Gre4nikov [31]
3 years ago
14

A movie theater has a seating capacity of 233. The theater charges $5.00 for children, $7.00 for students, and $12.00 of adults.

There are half as many adults as there are children. If the total ticket sales was $ 1692, How many children, students, and adults attended? I kinda need to know these answers asap. I have tried everything to try and solve it but nothing worked. Please help.
Mathematics
1 answer:
Marizza181 [45]3 years ago
6 0

Answer:

49 adults;  2*49 = 98 children  and  (207-3*49) = 60 students.

Step-by-step explanation:

hope this helps!! :))

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According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are re
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Answer:

Kindly check explanation

Step-by-step explanation:

Given the following :

P(brown) = 12% = 0.12

P(Yellow) = 15% = 0.15

P(Red) = 12% = 0.12

P(blue) = 23% = 0.23

P(orange) = 23% = 0.23

P(green) = 15% = 0.15

A.) Compute the probability that a randomly selected peanut M&M is not yellow.

P(not yellow) = P(Yellow)' = 1 - P(Yellow) = 1 - 0.15 = 0.85

B.) Compute the probability that a randomly selected peanut M&M is brown or red.

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C.) Compute the probability that three randomly selected peanut M&M’s are all brown.

P(brown) * P(brown) * P(brown)

0.12 * 0.12 * 0.12 =0.001728

D.) If you randomly select three peanut M&M’s, compute that probability that none of them are blue.

P(3 blue)' = 1 - P(3 blue)

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1 - P(3 blue) = 1 - 0.012167 = 0.987833

If you randomly select three peanut M&M’s, compute that probability that at least one of them is blue.

P(1 blue) + p(2 blue) + p(3 blue)

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0.23 + 0.0529 + 0.012167

= 0.295067

5 0
3 years ago
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