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2 years ago

48 divided by blank =6

Mathematics

2 answers:

Katarina [22]2 years ago

8 0

Answer:

8 would be your answer if I'm wrong pls let me know and I will edit soon as posable.

Step-by-step explanation:

the way I did it was doing 48 divided by 6 and I got the answer 8 meaning 8 would be the correct answer

poizon [28]2 years ago

6 0

Answer:

i think ANSWER IS 8

Step-by-step explanation:

48÷8 = 6

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What is the compound interest of 10400 at 12.7% for 4 year

Naddik [55]

The Compound Interest of 10400 at 12.7% for 4 years is 6378.

The principal amount is given as 10400.

The rate of interest is given as 12.7%.

The time period to be calculated is given as 4 years.

The compound interest for the given above is to be calculated.

<h3>What is compound interest?</h3>

Compound interest is the interest that we earn both on the principal amount and the interest we earn.

The formula used to calculate compound interest is:

$P [ (1 + \frac{R}{100} )^n - 1 ]$

Where P = principal amount, R = rate of interest, and n = number of years.

We have,

P = 10400

R = 12.7%

n = 4 years

Compound interest:

$P [ (1 + \frac{R}{100} )^n - 1 ]\\\\10400 [ (1 + \frac{12.7}{100} )^4 - 1 ]$

Now,

10400 [ ( 1 + 0.12.7 )^2 - 1 ]

10400 [ 1.127^4 - 1 ]

10400 [ 1.61322 - 1 ]

10400 x 0.6132

6377.56

Rounding to the nearest whole number.

We have,

Compound Interest = 6378.

Thus the Compound Interest of 10400 at 12.7% for 4 years is 6378.

Learn more about Compound Interest here:

brainly.com/question/13155407

#SPJ1

8 0

1 year ago

G with the definition of covariance, prove cov[(ay − b),(cy − d)] = accov(x, y ), where x, y are random variables and a, b, c, d

____ [38]

By definition of covariance,

$\mathrm{Cov}(X,Y)=\mathbb E[(X-\mathbb E[X])(Y-\mathbb E[Y])]$

$\mathrm{Cov}(X,Y)=\mathbb E[XY-\mathbb E[X]Y-X\mathbb E[Y]+\mathbb E[X]\mathbb E[Y]]=\mathbb E[XY]-\mathbb E[X]\mathbb E[Y]$

We have

$\mathbb E[(aX-b)(cY-d)]=\mathbb E[acXY-adX-bcY+bd]$

$=ac\mathbb E[XY]-ad\mathbb E[X]-bc\mathbb E[Y]+bd$

$\mathbb E[aX-b]=a\mathbb E[X]-b$

$\mathbb E[cY-d]=c\mathbb E[Y]-d$

$\mathbb E[aX-b]\mathbb E[cY-d]=ac\mathbb E[X]\mathbb E[Y]-ad\mathbb E[X]-bc\mathbb E[Y]+bd$

Putting everything together, we find the covariance reduces to

$\mathrm{Cov}(aX-b,cY-d)=ac(\mathbb E[XY]-\mathbb E[X]\mathbb E[Y])=ac\mathrm{Cov}(X,Y)$

as desired.

5 0

2 years ago

Write an equation of the line whose slope and y-intercept are respectively:

bezimeni [28]

2 and 7 because it will stay constant

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podryga [215]

Answer:

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Step-by-step explanation:

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Dmitry_Shevchenko [17]

Answer:

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Step-by-step explanation:

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5 0

2 years ago