The answer for this question is 4.5
The test statistic for the hypothesis would be 1.413.
Given that the participants in its new diet program lose, on average, more than 13 pounds and the mean weight loss of these participants as 13.8 pounds with a standard deviation of 3.1 pounds.
The objective is to text the advertisement's claim that participants in new diet program lose weight, on average, more than 13 pounds.
Hypothesis:
Null hypothesis:H₀:μ=13
Alternative hypothesis:Hₐ:μ>13
Here, μ be the mean weight loss of all participants.
n=30,
Degree of freedom n-1=30-1=29
=13.8 and s=3.1
To test the null hypothesis H₀, the value of test static would be calculated as follows:

Hence, the value of the test static for the hypothesis with the mean weight loss of these participants as 13.8 pounds with a standard deviation of 3.1 pounds is 1.413.
Learn more about hypothesis from here brainly.com/question/14783359
#SPJ4
Answer:
The orginal price was $33.09.
Step-by-step explanation:
You take 30% and move the decimal two places to the left, which gives you .3
Then mutiply .3 to $25.45. This gives you $7.64.
Add $7.64 to discounted price ($25.45) and you get $33.09.
II. Triangle ABC is obtuse and III. Triangle ABC is acute, because acute is less than 180° and obtuse is between 180° and 270°
Answer:
ok ill do it :-)
Step-by-step explanation: