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s344n2d4d5 [400]

3 years ago

10

Joseph walks his dog 4 times a day to make sure he gets enough exercise. If he walks his dog 2/3 of a mile each time he walks hi

m, how far will Joseph have walked his dog by the end of a 7 day week? Explain how you know.

1 answer:

charle [14.2K]3 years ago

7 0

Answer:

18 2/3 miles. 4 x 2/3 =8/3 x 7 = 56/3 ÷3 = 18 2/3 miles.

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What life cycle adaptation allows a seahorse to make lots of babies in a short amount of time? (2 points)

Zielflug [23.3K]

The seahorse make a lot of babies because the male carries the babies while the female makes more eggs.

<h3>What is mating?</h3>

Mating is the process in which opposite or hermaphroditic organisms pair for reproduction.

During mating between the male and female seahorse mates, the female seahorse puts her eggs in the male pouch and the male fertilises the egg in his pouch. The eggs develop into baby seahorse in the father pouch.

Find out more on mating at: brainly.com/question/922533

4 0

2 years ago

What is 80% of 35? (EXTRA CHARACTERS)

andrey2020 [161]

80% of 35 is 28 :) hope this helps!

5 0

2 years ago

Read 2 more answers

Identify the coordinates of the vertices of each figure after the similarity transformation.

bija089 [108]

Answer:

After translation:

Translation: (x, y) → (x-6, y-8)

W'X'Y'Z' = W'(-10, 0), X'(-10, -8), Y'(-18, -4), Z'(-14, 8)

After dilation:

Dilation: (x, y) → (2x, 2y), centered at (0, 0)

W''X''Y''Z'' = W'' (-20, 0), X'' (-8, 0) , Y'' (-24, 8), Z'' (-16, 32)

Step-by-step explanation:

Given the vertices of the Quadrilateral WXYZ

W(-4, 8)

X(-4, 0)

Y(-12, 4)

Z(-8, 16)

As the rule of translation is given by

Translation: (x, y) → (x-6, y-8)

So, after the translation the vertices of Quadrilateral WXYZ will be translated as:

W(-4, 8) → (x-6, y-8) ⇒ (-4-6, 8-8) = W'(-10, 0)

X(-4, 0) → (x-6, y-8) ⇒ (-4-6, 0-8) = X'(-10, -8)

Y(-12, 4) → (x-6, y-8) ⇒ (-12-6, 4-8) = Y'(-18, -4)

Z(-8, 16) → (x-6, y-8) ⇒ (-8-6, 16-8) = Z'(-14, 8)

Therefore,

W'X'Y'Z' = W'(-10, 0), X'(-10, -8), Y'(-18, -4), Z'(-14, 8)

Next, the rule of dilation is given by

Dilation: (x, y) → (2x, 2y), centered at (0, 0)

W'(-10, 0) → (2x, 2y) ⇒ (2(-10), 2(0)) = W'' (-20, 0)

X'(-4, 0) → (2x, 2y) ⇒ (2(-4), 2(0)) = X'' (-8, 0)

Y'(-12, 4) → (2x, 2y) ⇒ (2(-12), 2(4)) = Y'' (-24, 8)

Z'(-8, 16) → (2x, 2y) ⇒ (2(-8), 2(16)) = Z'' (-16, 32)

Therefore,

W''X''Y''Z'' = W'' (-20, 0), X'' (-8, 0) , Y'' (-24, 8), Z'' (-16, 32)

8 0

2 years ago

If you were constructing a TRIANGULAR FRAME, and you had wood in the length of 4inches, 4 inches, and 7 inches, would it make a

klemol [59]

Answer:

Yes

Step-by-step explanation:

In order to make a triangle with non-zero area, the sum of the shorter two sides must be greater than the longest side.

Here, 4 + 4 > 7, so the lengths can form a triangle.

8 0

3 years ago

f p(x) and q(x) are arbitrary polynomials of degreeat most 2, then the mapping< p,q >= p(-2)q(-2)+ p(0)q(0)+ p(2)q(2)defin

Natasha2012 [34]

We're given an inner product defined by

$\langle p,q\rangle=p(-2)q(-2)+p(0)q(0)+p(2)q(2)$

That is, we multiply the values of $p(x)$ and $q(x)$ at $x=-2,0,2$ and add those products together.

$p(x)=2x^2+6x+1$

$q(x)=3x^2-5x-6$

The inner product is

$\langle p,q\rangle=-3\cdot16+1\cdot(-6)+21\cdot(-4)=-138$

To find the norms $\|p\|$ and $\|q\|$ , recall that the dot product of a vector with itself is equal to the square of that vector's norm:

$\langle p,p\rangle=\|p\|^2$

So we have

$\|p\|=\sqrt{\langle p,p\rangle}=\sqrt{(-3)^2+1^2+21^2}=\sqrt{451}$

$\|q\|=\sqrt{\langle q,q\rangle}=\sqrt{16^2+(-6)^2+(-4)^2}=2\sqrt{77}$

Finally, the angle $\theta$ between $p$ and $q$ can be found using the relation

$\langle p,q\rangle=\|p\|\|q\|\cos\theta$

$\implies\cos\theta=\dfrac{-138}{22\sqrt{287}}\implies\theta\approx1.95\,\mathrm{rad}\approx111.73^\circ$

4 0

3 years ago