Question

SOLVE APPLICATION USING ALGEBRA. TYPE THE EQUATION OR INEQUALITY AND PLEASE SHOW WORK. a) A rectangle with perimeter 18 cm has length that is 3 cm more than twice its width. Find the dimensions of the rectangle.

Answer 1

Answer:

$w=2\\l=7$

Step-by-step explanation:

$l+l+w+w=18\\\\2w+3=l\\\\2w+3+2w+3+w+w=18\\6w+6=18\\6w=12\\w=2\\\\2w+3=l\\2*2+3=l\\4+3=l\\l=7$

Answer 2

Answer:

3 cm by 6 cm

Step-by-step explanation:

Represent the length and width by L and W.  

The perimeter is P = 2L + 2W, and here the perimeter is 18 cm.

Finally, L = W + 3 cm.  substituting W + 3 cm for L in the above equation, we get:

18 cm = 2(W + 3) + 2W, or (after reduction)

9 cm = W + 3 cm + W

Then 2W = 6 cm, or W = 3 cm.

Then the length is L = W + 3, or 3 cm + 3cm = 6 cm

The dimensions of the rectangle are 3 cm by 6 cm.

Check:  Does 2(3 cm) + 2(6 cm) = 18 cm?  Yes