2 years ago

Find three consecutive integers such that twice the smallest is 12 more than the largest.

Mathematics

1 answer:

iris [78.8K]2 years ago

4 0

Answer:

14, 15, 16

Step-by-step explanation:

Let integers equal:

x, x + 1, x + 2

2x = 12 + (x + 2)

2x = 12 + x + 2

2x = 14 + x

2x - x = 14

x = 14

x + 1 = 14 + 1 = 15

x + 2 = 14 + 2 = 16

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