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OleMash [197]
3 years ago
15

What situation can be modeled using the same equation -4 + 4 equals 0​

Mathematics
1 answer:
Lorico [155]3 years ago
7 0
The answer is B because it is at -4 then increases 4 so now it is 0 degrees .
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Can you make all the numbers from 1 to 20 using 4 fours?
Effectus [21]

Answer: no you can't you can only use 5 numbers when going by 4's

Step-by-step explanation: 4, 8, 12, 16, 20

8 0
2 years ago
Read 2 more answers
chris has a collection of dimes and quarters worth $4.25. if she has 23 coins total, how many quarters does she have.
ohaa [14]

Answer:

b

Step-by-step explanation:

3 0
3 years ago
What is the answer of a ?
Scorpion4ik [409]

Answer:

<h2>2.2</h2>

Step-by-step explanation:

Use the cosine law (look at the picture).

We have:

a=a\\b=4\\c=3\\\gamma=32^o

a^2=4^2+3^2-2(4)(3)\cos32^o

\cos32^o\approx0.848 → look at the second picture

a^2=16+9-24(0.848)\\\\a^2=25-20.352\\\\a^2=4.648\to a=\sqrt{4.648}\\\\a\approx2.2

4 0
3 years ago
Solve the 3 × 3 system shown below. Enter the values of x, y, and z. X + 2y – z = –3 (1) 2x – y + z = 5 (2) x – y + z = 4 (3)
Svet_ta [14]
<h2>Answer:</h2>

\boxed{x=1, \y=-1, \ z=2}

<h2>Step-by-step explanation:</h2>

We will use the Gaussian elimination method to solve this problem. To do so, let's follow the following steps:

Step 1: Let's multiply first equation by −2. Next, add the result to the second equation. So:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\~~ x&-~~~~~ y&+~~~~ z&~=~4\end{array}

Step 2: Let's multiply first equation by −1. Next, add the result to the third equation. Thus:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\&-~~~3~ y&+~~2~ z&~=~7\end{array}

Step 3: Let's multiply second equation by −35, Next, add the result to the third equation. Therefore:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\&&+~~\frac{ 1 }{ 5 }~ z&~=~\frac{ 2 }{ 5 }\end{array}

Step 4: solve for z, then for y, then for x:

\frac{ 1 }{ 5 } ~ z & = \frac{ 2 }{ 5 } \\ \\ \boxed{z & = 2}

-5y+3z &= 11\\-5y+3\cdot 2 &= 11\\ \\ \boxed{y &= -1}

By substituting y=-1 \ and \ z=2 into the first equation, we get the x. So:

x+2(-1)-2=-3 \\ \\ x-2-2=-3 \\ \\ \boxed{x=1}

6 0
3 years ago
Read 2 more answers
A kid traveled a distance of 9 km by bike, and then walked a distance of km.
vichka [17]

Answer:

Step-by-step explanation:

The question is incomplete. Here is the complete question;

A kid traveled a distance of 9 km by bike, and then walked a distance of x km.

a.Find the total distance traveled in terms of  x

b. If the total distance was less than 30 km, form an inequality in x, and

then solve it!

a) Total distance = distance travelled by bike + distance walked

Total distance = 9km + xkm

Total distance = (9+x)km

b)  If the total distance was less than 30 km, the inequality representing this is;

9+x < 30

Subtract 9 from both sides;

9+x-9 < 30-9

x < 21

hence the solution to the inequality is x< 21

3 0
2 years ago
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