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dalvyx [7]
3 years ago
7

A random sample of 64 bags of white cheddar popcorn weighed, on average, 5.45 ounces with a standard deviation of 0.25 ounce. te

st the null hypothesis that μ=5.5 ounces against the alternative hypothesis, μ<5.5 ounces, at the 0.05 level of significance. what is the p-value?
Mathematics
1 answer:
Licemer1 [7]3 years ago
5 0
Give me a 1 i need anwser choices please
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Solve the equation. Check your solution. - 12/x+24/x-2 =4
Lorico [155]

Answer: 6

Step-by-step explanation:

I did it with LCM


-12(x-2) + (24x) = 4x(x-2)

- > -24x+24 + 24x = 4x^{2} -8x\\- > 0 = 4x^{2}-8x-24\\

using the quadratic formula, u get 6 and -1

8 0
1 year ago
I will give brainiest to whoever answers correctly !!
777dan777 [17]

Answer:

The finance charge is 23,028

Step-by-step explanation:

I think you just are supposed to just add and multiply in this case

4 0
3 years ago
Please help with both questions
enyata [817]

Answer:

See comment

Step-by-step explanation:

13 lawns

8 0
2 years ago
Me.Durham is contemplating which chauffeured car service to the airport. The first costs $30 up front and $3 per kilometer. The
Semmy [17]

Answer: 45 dollars and it was a distance of 5 kilometers

Step-by-step explanation: What i did was start with 30, then keep adding 3 till i got the a multiple of 5.

30 + 3 = 33

33 + 3 = 36

36 + 3 = 39

39 + 3 = 42

42 + 3 = 45

So already i know that it is 5 kilometers, because i added 3 to 30 five times.

No i will do that with the second company

20 + 5 = 25

25 + 5 = 30

30 + 5 = 35

35 + 5 =  40

40 + 5 = 45

That is also 5 kilometers, because i added 5 to 20 five times. I also know they are the same price, because they both added to 45 dollars.

Thats how i solved it.

I really hope that helps!

8 0
3 years ago
Let f(x) = cxe−x2 if x ≥ 0 and f(x) = 0 if x &lt; 0.
sergij07 [2.7K]

(a) If <em>f(x)</em> is to be a proper density function, then its integral over the given support must evaulate to 1:

\displaystyle\int_{-\infty}^\infty f(x)\,\mathrm dx = \int_0^\infty cxe^{-x^2}\,\mathrm dx=1

For the integral, substitute <em>u</em> = <em>x</em> ² and d<em>u</em> = 2<em>x</em> d<em>x</em>. Then as <em>x</em> → 0, <em>u</em> → 0; as <em>x</em> → ∞, <em>u</em> → ∞:

\displaystyle\frac12\int_0^\infty ce^{-u}\,\mathrm du=\frac c2\left(\lim_{u\to\infty}(-e^{-u})-(-1)\right)=1

which reduces to

<em>c</em> / 2 (0 + 1) = 1   →   <em>c</em> = 2

(b) Find the probability P(1 < <em>X </em>< 3) by integrating the density function over [1, 3] (I'll omit the steps because it's the same process as in (a)):

\displaystyle\int_1^3 2xe^{-x^2}\,\mathrm dx = \boxed{\frac{e^8-1}{e^9}} \approx 0.3678

5 0
2 years ago
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