The equation, in slope-intercept form, of the line that is parallel to the given line and passes through the point (0, 12) is y = -5x + 1
<h3>Equation of a line</h3>
A line is the distance between two points
Given the equation of a line expressed as 10x + 2y = -2. Determine the slope
2y = -10x -2
y = -5x - 1
Slope of the line is -5
The equation of a line in point-slope form is y - y1 = m(x-x1)
Substitute the point and the slope of the parallel line
y - 12 = -5(x - 0)
y - 12 = -5x
y = -5x + 12
Hence the equation, in slope-intercept form, of the line that is parallel to the given line and passes through the point (0, 12) is y = -5x + 12
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Step-by-step explanation:
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Answer:
Step-by-step explanation:
Givens
Let the width = x
Let the length = x + 5
Equation
2w + 2W = P
Solution
2x + 2(x + 5) = 192 Remove the brackets <=== Answer
2x + 2x + 10 = 192 Combine like terms
4x + 10 = 192 Subtract 10 from both sides
4x = 192 - 10
4x = 182 Divide by 4
4x/4 = 182/4
x = 45.5