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netineya [11]
3 years ago
7

Can i get help on this

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
8 0

Answer:

Student 1

Student 2

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Uber is now charging a $2.50 flat rate in addition to $0.75 per mile for your ride. Janae can spend at most $13 on her Uber Ride
Alex777 [14]

Answer:

  • B: 10

Step-by-step explanation:

<u>Full charge can be expressed as equation:</u>

  • c = 2.5 + 0.75m, where c- charge, m- miles

<u>The limit for charge is $13, then we got inequality:</u>

  • 0.75m + 2.5 ≤ 13
  • 0.75m ≤ 9.5
  • m ≤ 9.5/0.75
  • m ≤ 12.66

Option B: 10 is correct as the only number satisfying the inequality

7 0
3 years ago
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The hypotenuse of a right triangle measures 10 inches, and the side opposite to ∠θ, one of the non-right angles, is 5 inches lon
NISA [10]
The measure of angle theta is 30 degrees. 

This is a 30-60-90 triangle where the short leg is half that of the hypotenuse. The short leg is opposite the smallest angle 30 degrees. 

You can use trig to find that
sin(angle) = opposite/hypotenuse
sin(theta) = 5/10
sin(theta) = 0.5
theta = arcsin(0.5)
theta = 30 degrees
7 0
3 years ago
Whats the answer, to the question below
NISA [10]

The answer to this problem is 5.

6 0
3 years ago
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Translate each sentence into an equation.
iogann1982 [59]
Answers

1. 1/4 x M-6= (m+9)x2


Ps. Couldn’t do 4
5 0
1 year ago
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Which value of x does not satisfy the equation sin^2x + sin x = 0
zzz [600]

Answer:

x \neq 0 \pm \pi \cdot i, \forall i \in \mathbb{N}_{O} and x \neq \frac{3\pi}{2}\pm 2\pi \cdot j, \forall j \in \mathbb{N}_{O}.

Step-by-step explanation:

The equation can be simplified with the help of trigonometric identities:

\sin x \cdot (\sin x + 1) = 0

Which means that equation is equal to zero if any component of the product is zero. The solutions of the expression are:

a) \sin x

x = 0 \pm \pi\cdot i,\forall i \in \mathbb{N}_{O}

b) \sin x + 1

\sin x + 1 = 0

\sin x = -1

x = \frac{3\pi}{2} \pm 2\pi\cdot i,\forall i \in \mathbb{N}_{O}

Any value different of both subsets do not satisfy the equation described above.

8 0
3 years ago
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