Can i get help on this

How would I graph this?

elena55 [62]

$y\leq 2x-5$

↝ x-intercept

$2x-5=0\\2x=5\\x=\frac{5}{2}$

↝ y-intercept

y = -5

↝ $y\leq 2x-5$ means that the shade/area is below the graph as shown in the first picture.

$y\leq -\frac{1}{2}x-3$

↝ x-intercept

$-\frac{1}{2}x-3=0\\-x-6=0\\-x=6\\x=-6$

↝ y-intercept

y = -3

↝ Since it's "≤" therefore. The shade/area is below the graph. For second picture.

First picture is first inequality

Second picture is second inequality.

3 0

3 years ago

Number 25 someone help me

Fittoniya [83]

The area of a triangle is given by the formula $A= \frac{1}{2}Bh$ , where B is the base and h is the height. We can rearrange this formula to solve for B.

$\dfrac{A}{ \frac{1}{2}h} = B\\ \\\\\dfrac{2A}{h} = B$ .

We plug in the given area, 640 square millimeters, and the given height, 32 millimeters.

$B= \dfrac{2(640)\ mm^2}{32 \ mm} = 40 \ mm$ .

40 mm is our final answer.

5 0

3 years ago

An employee was randomly chosen from a company. If the expected value of the age of the employee is _____ years old, the mean ag

Vinil7 [7]

This employee who was randomly chosen represents the population of the company. This means that, any parameter measured through this employee can be considered as the mean or average value for the whole population (the company).

Based on this, taking the age of the employee as the desired parameter, the age of this employee will be considered as the average or mean age for the whole company. This means that the age of the employee and the mean age of all employees are equal.

Therefore, the answer is C) 32, 32
<span>An employee was randomly chosen from a company. If the expected value of the age of the employee is 32 years old, the mean age of all the employees in the company is 32 years old.</span>

5 0

4 years ago

Read 2 more answers

A skier is trying to decide whether or not to buy a season ski pass. A daily pass costs $69. A season ski pass costs $350. The

zalisa [80]

Divide the season pass cost by the daily capstone:

350 / 69 = 5.07

They would have to ski 6 days for the season pass to be less expensive

7 0

3 years ago

Sin^2(x/2)=sin^2x <br> Find the value of x

Veronika [31]

$\sin^2\dfrac x2=\sin^2x$
$\dfrac{1-\cos x}2=1-\cos^2x$
$1-\cos x=2-2\cos^2x$
$2\cos^2x-\cos x-1=0$
$(2\cos x+1)(\cos x-1)=0$
$\implies\begin{cases}2\cos x+1=0\\\cos x-1=0\end{cases}$ $\implies\begin{cases}\cos x=-\frac12\\\cos x=1\end{cases}$

The first case occurs in $0\le x$ for $x=\dfrac{2\pi}3$ and $x=\dfrac{4\pi}3$ . Extending the domain to account for all real $x$ , we have this happening for $x=\dfrac{2\pi}3+2n\pi$ and $\dfrac{4\pi}3+2n\pi$ , where $n\in\mathbb Z$ .

The second case occurs in $0\le x$ when $x=0$ , and extending to all reals we have $x=2n\pi$ for $n\in\mathbb Z$ , i.e. any even multiple of $\pi$ .

6 0

3 years ago