Solve each system by substitution. Show your work.
1 answer:
1) y = -3x - 1
Y= 3x - 7
- 3x -1= 3x -7
Like terms
-3x -3x = -7 + 4
A negative and a negative is a positive
-3x + - 3x = -6x because a positive and a negative is a negative
-7 + 1 = - 6
Hence
- 6 x = -6
Divide both sides by -6
Which gives u
X = 1
Now substitute x = 1 into one of the original equations
Y = 3x - 7
Y = 3*1 - 7
Y = 3 - 7
Look at the bigger number sign
Therefore
Y = - 4
So when x = 1, y = -4
It’s really the same for the rest of the questions to be honest
Y= 3x - 7
- 3x -1= 3x -7
Like terms
-3x -3x = -7 + 4
A negative and a negative is a positive
-3x + - 3x = -6x because a positive and a negative is a negative
-7 + 1 = - 6
Hence
- 6 x = -6
Divide both sides by -6
Which gives u
X = 1
Now substitute x = 1 into one of the original equations
Y = 3x - 7
Y = 3*1 - 7
Y = 3 - 7
Look at the bigger number sign
Therefore
Y = - 4
So when x = 1, y = -4
It’s really the same for the rest of the questions to be honest
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