Question

Please help me. I will be giving 50 points, brainliest, a friend request, 5 stars and a heart. Please give an explanation as well.

Answer 1

Answer:

Step-by-step explanation:

Let older brother age be x and the age difference between the brothers be y

Younger brother's current age = x - y

When older brother's age was at x - y, younger brother's age was x - 2y = 2

When young brother's age will be at x, older brother's age will be x + y = 20

Subtracting the first equation from the second: 3y = 18

y = 6

x = 14

So the older brother is 14 and the younger brother is 8.

Sum of three son's ages now = 15 + 11 + 7 = 33

Daddy's age now = 45

Age difference = 12

Each year, daddy's age goes up by 1 while the sum of three son's ages goes up by 3.

Dividing the age difference by the difference in age gain, 12 / (3 -1) = 12 / 2

= 6

So in 6  years when daddy is 51 and the sum of sons at 21, 17 and 13 will be equal.

Answer 2

Answer:

Step-by-step explanation:

older bro age is x

younger bro age is y

age diff = x - y

it was (x-y) years ago when older bro was at age y

younger bro age then was y - (x - y) =2

2y - x = 2

younger bro will be at age x in (x-y) years

older bro age then will be x + (x-y) = 20

2x - y = 20

4x - 2y = 40

adding 2y - x = 2

3x = 42

x = 14

y = 2*14 - 20 = 8

daddy' age, 45 is 12 over the sum of sons (15, 11 and 7)

in 1 yr, dad age +1 n sum of sons +3 = difference of 2

so in 12/2 = 6 yrs they will be the same