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rosijanka [135]
3 years ago
9

Please answer and help me on this question!​

Mathematics
1 answer:
Nady [450]3 years ago
4 0
<h3>Answer: 10.1 cm approximately</h3>

=====================================================

Explanation:

The double tickmarks show that segments DE and EB are the same length.

The diagram shows that DB = 16 cm long

We'll use these facts to find DE

DE+EB = DB

DE+DE = DB

2*DE = DB

DE = DB/2

DE = 16/2

DE = 8

-------------

Now let's focus on triangle DEC. We just found the horizontal leg is 8 units long. The vertical leg is EC which is unknown for now. We'll call it x. The hypotenuse is CD = 9

Use the pythagorean theorem to find x

a^2+b^2 = c^2

8^2+x^2 = 9^2

64+x^2 = 81

x^2 = 81 - 64

x^2 = 17

x = sqrt(17)

That makes EC to be exactly sqrt(17) units long.

If you follow those same steps for triangle ADE, then you'll find the missing length is AE = 6

---------------

So,

AC = AE+EC

AC = 6 + sqrt(17)

AC = 10.1231056256177

AC = 10.1 cm approximately

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Step-by-step explanation:

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What is the constant of variation for the quadratic variation? x=2,3,4,5,6 y= 32,72,128,200,288
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Hello,
y=a*x² ==>
32=a*2²==>a=32/4=8
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