Solve the inequality. 8p 2 > 3p

Madison to read a book that is 260 page and her mom said she can take a break and she is 30% finish how far does she need to rea

aliya0001 [1]

30% is 3/10. 260 times 3/10 is 780/10, or 78. She read 78 pages. 260 - 78 is 182 pages left.

3 0

3 years ago

Read 2 more answers

Will mark as brainliest if correct

lana [24]

Answer:

wala sa choices ang sagot.

ANS: 128

EXPLANATION

a(9)=14+2(9-1)

a(9)=14+2(8)

a(9)=16(8)

9= 128

yan sagot ko po

4 0

3 years ago

How to do this question plz answer

const2013 [10]

9514 1404 393

Answer:

60

Step-by-step explanation:

The exterior angles of the polygon are the supplement of the interior angles, so are ...

180° -174° = 6° . . . . measure of each exterior angle

The sum of exterior angles is 360°, so ...

n(6°) = 360°

n = 360°/6° = 60

The polygon has 60 sides.

7 0

3 years ago

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SOMEONE HELP ME PLEASE

Novay_Z [31]

Y - 5 = -1/2(x-1)

hope this helps!

3 0

3 years ago

Based on an indication that mean daily car rental rates may be higher for Boston than for Dallas, a survey of eight car rental c

Elina [12.6K]

Answer:

$t=\frac{(47 -44)-(0)}{3\sqrt{\frac{1}{8}+\frac{1}{9}}}=2.058$

The degrees of freedom are:

$df=8+9-2=15$

And the p value would be:

$p_v =P(t_{15}>2.058) =0.0287$

Since we have a p value lower than the significance level given of 0.05 we can reject the null hypothesis and we can conclude that the true mean for car rental rates in Boston are signiﬁcantly higher than those in Dallas

Step-by-step explanation:

Data given

$n_1 =8$ represent the sample size for group Boston

$n_2 =9$ represent the sample size for group Dallas

$\bar X_1 =47$ represent the sample mean for the group Boston

$\bar X_2 =44$ represent the sample mean for the group Dallas

$s_1=3$ represent the sample standard deviation for group Boston

$s_2=3$ represent the sample standard deviation for group Dallas

We can assume that we have independent samples from two normal distributions with equal variances and that is:

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

Let the subindex 1 for Boston and 2 for Dallas we want to check the following hypothesis:

Null hypothesis: $\mu_1 \leq \mu_2$

Alternative hypothesis: $\mu_1 > \mu_2$

The statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

Where t follows a t student distribution with $n_1+n_2 -2$ degrees of freedom and the pooled variance $S^2_p$ is given by this formula:

$\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

Replacing we got:

$\S^2_p =\frac{(8-1)(3)^2 +(9 -1)(3)^2}{8 +9 -2}=9$

And the deviation would be just the square root of the variance:

$S_p=3$

The statitsic would be:

$t=\frac{(47 -44)-(0)}{3\sqrt{\frac{1}{8}+\frac{1}{9}}}=2.058$

The degrees of freedom are:

$df=8+9-2=15$

And the p value would be:

$p_v =P(t_{15}>2.058) =0.0287$

Since we have a p value lower than the significance level given of 0.05 we can reject the null hypothesis and we can conclude that the true mean for car rental rates in Boston are signiﬁcantly higher than those in Dallas

5 0

3 years ago

Solve the inequality. 8p 2 > 3p - 15