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3 years ago

Solve please. Correctly -2x + 5x = 3x - 3

Mathematics

2 answers:

Ugo [173]3 years ago

8 0

3x=3x -3 which would equal infinite or no solution. Hope this helps !

Stella [2.4K]3 years ago

8 0

Answer:

no solution, the sides aren't equal

Step-by-step explanation:

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option 1 drop down are: even-odd identity, quotient identity, Pythagorean identity, double-number identity.option 2 drop down ar

motikmotik

Answer:

The equation is given below as

$\frac{\cos2x}{\cos x}=\cos x-\sin x\tan x$

Step 1:

We will work on the left-hand side, we will have

$\begin{gathered} \cos x-\sin x\tan x \\ \text{recall that,} \\ Quoitent\text{ identity is} \\ \tan x=\frac{\sin x}{\cos x} \end{gathered}$

By substituting the identity above, we will have

$\begin{gathered} \cos x-\sin x\tan x=\cos x-\frac{\sin x.\sin x}{\cos x}=\cos x-\frac{\sin^2x}{\cos x} \\ \end{gathered}$

Here, we will make use of the quotient identity

Step 2:

By writings an expression, we will have

$\begin{gathered} \cos x-\sin x\tan x=\cos x-\frac{\sin x.\sin x}{\cos x} \\ \cos x-\sin x\tan x=\frac{\cos^2x-\sin^2x}{\cos x} \end{gathered}$

Here, we will use the definition of subtraction

$\cos x-\frac{\sin^2x}{\cos x}$

Step 3:

We will apply the double number identity given below

$\begin{gathered} \cos 2\theta=\cos (\theta+\theta)=\cos ^2\theta-\sin ^2\theta \\ \cos 2x=cos(x+x)=\cos ^2x-\sin ^2x \end{gathered}$

By applying this, we will have

$\frac{\cos^2x-\sin^2x}{\cos x}=\frac{\cos2x}{\cos x}$

Here, we will use the double number identity

$\frac{\cos^2x-\sin^2x}{\cos x}$

5 0

1 year ago

Use the distance formula distance, to find the distance to the nearest tenth , between each pair of points A(6,2) and D(-3,-2)

marusya05 [52]

Answer:

The distance between A and D to the nearest tenth is;

$9.8\text{ units}$

Explanation:

Given the two points;

$A(6,2)\text{ and D(-3,-2)}$

Applying the distance between two points formula;

$d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}$

substituting the given coordinates we have;

$\begin{gathered} AD=\sqrt[]{(-3-6)^2+(-2-2)^2} \\ AD=\sqrt[]{(-9)^2+(-4)^2} \\ AD=\sqrt[]{81+16} \\ AD=\sqrt[]{97} \end{gathered}$

Simplifying;

$\begin{gathered} AD=9.8488578 \\ AD\approx9.8 \end{gathered}$

Therefore, the distance between A and D to the nearest tenth is;

$9.8\text{ units}$

4 0

1 year ago

Split 18 into the ratio 1:2<br>

Eva8 [605]

Answer:

6:12

Step-by-step explanation:

Add 1+2=3

18/3=6

6x1=6

6x2=12

Out it back in the ratio

6:12

8 0

2 years ago

If 17 is 10 more than half of the number what is its original number

disa [49]

I suppose its 7, subtracted

4 0

3 years ago

Read 2 more answers

A.)0.406<br> B.)0.435<br> C.)0.303<br> D.)0.154

Serggg [28]

I think it should be option d

3 0

3 years ago