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2 years ago

Which composition of similarity transformations maps polygon ABCD to polygon A’B’C’D’

Mathematics

1 answer:

Ugo [173]2 years ago

4 0

Hey there!

Unless the smaller object was rotated 360° (in which case the rotation wouldn't have to be mentioned), you can see that all of the lines are still in the same place and that it wasn't rotated at all. This eliminated any answer option that mentions a rotation, which is A and C.

Also, if you count the units of one of the straight lines – for example, line AB and A'B' – you can see that the smaller object is four times smaller than the larger object. In the case of line AB and A'B', line AB is 8 units long and A'B' is 2 units long. This means that the scale factor is $1$ .

Lastly, the smaller object was moved from its initial location, which would be in the center of the larger object if it wasn't moved after being scaled down.

The answer will be, "a dilation with a scale factor of $1$ and then a translation."

Hope this helped you out! :-)

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Anna35 [415]

Answer:

x = number of bicycles = 35

y = number of cars = 55

Step-by-step explanation:

Let

x = number of bicycles

y = number of cars

x + y = 80 (1)

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From (1)

x = 80 - y

Substitute x = 80 - y into (2)

2x + 4y = 270 (2)

2(80 - y) + 4y = 270

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6 0

3 years ago

each of the 20 balls is tossed independently and at random into one of the 5 bins. let p be the probability that some bin ends u

amm1812

if p is the probability that some bin ends up with 3 balls and q is the probability that every bin ends up with 4 balls. pq is 16.

First, let us label the bins with 1,2,3,4,5.

Applying multinomial distribution with parameters n=20 and p1=p2=p3=p4=p5=15 we find that probability that bin1 ends up with 3, bin2 with 5 and bin3, bin4 and bin5 with 4 balls equals:

5−2020!3!5!4!4!4!

But of course, there are more possibilities for the same division (3,5,4,4,4) and to get the probability that one of the bins contains 3, another 5, et cetera we must multiply with the number of quintuples that has one 3, one 5, and three 4's. This leads to the following:

p=20×5−2020!3!5!4!4!4!

In a similar way we find:

q=1×5−2020!4!4!4!4!4!

So:

pq=20×4!4!4!4!4!3!5!4!4!4!=20×45=16

thus, pq = 16.

To learn more about Probability visit: brainly.com/question/29508225

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