Find the ratio of a:b if it is given that a+2b/11= b/3 please answer thanks!

Mathematics

2 answers:

Serjik [45]2 years ago

7 0

Answer:

3(a+2b)=11b

3a+6b=11b

3a=5b

a/b=5/3

a:b=5:3

stepladder [879]2 years ago

6 0

Answer:

a:b = 5:3

Step-by-step explanation:

I do RSM too, just type in 5:3! Good luck and have a wonderful day.

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A tank has capacity 6 L and initially contains 11 mg of salt dissolved in 3 L of water. A solution containing 1 mg/L of salt ent

BlackZzzverrR [31]

Answer:

The answer is below

Step-by-step explanation:

a) The maximum capacity of he tank is 6 L and initially it contains 11 mg of salt dissolved in 3 L of water. Solution enters the tank at a rate of 3 L/hr, therefore in x hours, the amount of water that have entered the tank = 3x.

Solution also leaves the tank at a rate of 2L/hr, therefore in x hours, the amount of water that have left the tank = 2x

Hence the amount of water present in the tank at x hours is given as:

3 + 3x - 2x = 3 + x

The time taken to full the tank can be gotten from:

3 + x = 6

x = 6 - 3

x = 3 hr

$\frac{dQ}{dx}=3-\frac{2Q}{3+x}\\ \\\frac{dQ}{dx}+\frac{2Q}{3+x}=3\\\\let\ u'=\frac{2u}{3+x}\\\\\frac{u'}{u}=\frac{2Q}{3+x}\\\\ln(u)=2ln(3+x)\\\\u=(3+x)^2\\\\(3+x)^2Q]'=3(3+x)^2\\\\(3+x)^2Q=(3+x)^3+c\\\\Q(0)=11\\\\(3+0)^2(11)=(3+0)^3+c\\\\x=72\\\\Q=x+3+\frac{72}{(x+3)^2}\\ \\Q(3)=3+3+\frac{72}{(3+3)^2}=8\ mg$