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Anettt [7]
3 years ago
12

PLEASE HELP!!!! Solve the system of equation. Write the solution as a coordinate point.

Mathematics
1 answer:
Dovator [93]3 years ago
5 0

We can just substitute y = 4x+1 in the second equation.

6x-2(4x+1)=-3\\6x-8x-2=-3\\6x-8x-2+3=0\\-2x+1=0\\-2x=-1\\x=\frac{1}{2}

We know the value of x, substitute x in any equations to get the y-value.

4x+1=y\\4(\frac{1}{2})+1=y\\2+1=y\\3=y

The value of y is 3 and the value of x is 0.5 aka 1/2

Since you want the solution as a point then It's below here.

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What is the area of this polygon in square units ?
Maru [420]

Answer:

9 units²

Step-by-step explanation:

This is a trapezium.

The length of the two parallel lines (on top and bottom) are 5 units and 1 units.

The height of the trapezium is 3 units. Using these information, we can apply the formula for area of trapezium to find the answer.

Area = 1/2 (5 + 1) x 3 = 9 units²

7 0
3 years ago
49x^2=-21x-2 quadratic functions
lara [203]

Answer: 49x^2=-21x-2 quadratic functions -1/7and -2/7    



Step-by-step explanation:

Quadratic function:

In elementary algebra, the quadratic formula is a formula that provides the solution to a quadratic equation. There are other ways of solving a quadratic equation instead of using the quadratic formula, such as factoring, completing the square, graphing and others.

Move terms to the left side

49x^{2}  =-21x-2

49x^{2}  -(-21x-2) =0

 Distribute

49x^{2}  -(-21x-2) =0

49x^{2}+21x+2=0

Use the quadratic formula



 x=(-b±√b^{2}  -4ac  ) / 2a

                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                   

Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.

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let, a=49

b=21

c=2

 Replace with values in this equation

X=(-b±√b^{2}  -4ac  ) / 2a

Simplify

Evaluate the exponent

Multiply the numbers

Subtract the numbers

Evaluate the square root

Multiply the numbers

x=(-21±7) /98

Separate the equations

To solve for the unknown variable, separate into two equations: one with a plus and the other with a minus.Separate

x=(-21+7) /98

x=(-21-7) /98

Solve

Rearrange and isolate the variable to find each solution

x=-1/7

x=-2/7



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