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Anettt [7]
2 years ago
12

PLEASE HELP!!!! Solve the system of equation. Write the solution as a coordinate point.

Mathematics
1 answer:
Dovator [93]2 years ago
5 0

We can just substitute y = 4x+1 in the second equation.

6x-2(4x+1)=-3\\6x-8x-2=-3\\6x-8x-2+3=0\\-2x+1=0\\-2x=-1\\x=\frac{1}{2}

We know the value of x, substitute x in any equations to get the y-value.

4x+1=y\\4(\frac{1}{2})+1=y\\2+1=y\\3=y

The value of y is 3 and the value of x is 0.5 aka 1/2

Since you want the solution as a point then It's below here.

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Simplified form of (3-5i)^2​
Likurg_2 [28]

Answer:

-16 - 30i

Step-by-step explanation:

(3-5i)^2​ = (3-5i) * ​(3-5i)

Applying the "FOIL" method of expanding this expression through multiplication, we get:

9 - 15i - 15i - 25    (since i^2 = -1)

Simplifying this result, we get -16 - 30i

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3 years ago
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Pachacha [2.7K]

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Step-by-step explanation:

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2 years ago
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Paladinen [302]
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8 0
2 years ago
f of x equals 4 x over quantity x squared minus 16. Show all work to identify the asymptotes and zero of the function.
yuradex [85]

Given:

The function is

f(x)=\dfrac{4x}{x^2-16}

To find:

The asymptotes and zero of the function.

Solution:

We have,

f(x)=\dfrac{4x}{x^2-16}

For zeroes, f(x)=0.

\dfrac{4x}{x^2-16}=0

4x=0

x=0

Therefore, zero of the function is 0.

For vertical asymptote equate the denominator of the function equal to 0.

x^2-16=0

x^2=16

Taking square root on both sides, we get

x=\pm \sqrt{16}

x=\pm 4

So, vertical asymptotes are x=-4 and x=4.

Since degree of denominator is greater than degree of numerator, therefore, the horizontal asymptote is y=0.

8 0
3 years ago
Kris has 4 yards of ribbon. it takes 2/3 yard to wrap one package. How many packages can Kris wrap?
Serggg [28]

Answer:

C. 6 packages

Step-by-step explanation:

4 divided by 2/3

=>4x3/2=6

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