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Anettt [7]
2 years ago
12

PLEASE HELP!!!! Solve the system of equation. Write the solution as a coordinate point.

Mathematics
1 answer:
Dovator [93]2 years ago
5 0

We can just substitute y = 4x+1 in the second equation.

6x-2(4x+1)=-3\\6x-8x-2=-3\\6x-8x-2+3=0\\-2x+1=0\\-2x=-1\\x=\frac{1}{2}

We know the value of x, substitute x in any equations to get the y-value.

4x+1=y\\4(\frac{1}{2})+1=y\\2+1=y\\3=y

The value of y is 3 and the value of x is 0.5 aka 1/2

Since you want the solution as a point then It's below here.

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Given:

Triangle LJK.

LJ = 89 in, LK = 28 in and m∠L = 42°

To find:

The length of missing side JK.

Solution:

LJ = k = 89

LK = j = 28

JK = l = ?

Using law of cosine:

l^{2}=j^{2}+k^{2}-2 jk \cdot \cos L

Substitute the given values.

l^{2}=28^{2}+89^{2}-2 \cdot 28 \cdot 89 \cdot \cos 42^\circ

l^{2}=784+7921-4984 \cdot (0.7)

l^{2}=784+7921-4984 \cdot (0.7431)

l^{2}=784+7921-3703.6

l^{2}=5001.4

Taking square root on both sides.

l=70.7

The length of the missing side is 70.7 in.

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3 years ago
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abruzzese [7]

Answer:

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Using Pythagoras' identity in this right angle

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