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MAVERICK [17]
3 years ago
7

At a farm four employees harvest 48 pounds of food over a certain number of hours each employee works the number of hours shown

Mathematics
1 answer:
love history [14]3 years ago
7 0

Complete question :

At a farm, four employees harvest 48 pounds of food over a certain numbers of hours. Each employee works the numbered of hours shown. Employee A: 6 hours employee B: 4 hours employee C: 6 hours employee D: 8 hours The number of pounds of food harvested by each employee is proportional to the number of hours worked. Fill in the table with the amount of food, in pounds, each employee harvested.

Answer:

A = 12 lbs ;

B = 8 lbs

C = 12 lbs

D = 16 lbs

Step-by-step explanation:

Total hours worked :

(A + B + C + D)

(6 + 4 + 6 + 8) hours = 24 hours

Total pounds of food = 48 pounds

Pounds harvested per hour = 48 pounds / 24 hours = 2 pounds per hour

Amount of food harvested by each employee :

A = 6 * 2 = 12 pounds

B = 4 * 2 = 8 pounds

C = 6 * 2 = 12 pounds

D = 8 * 2 = 16 pounds

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on the football team, two out of every seven players are seniors. if the team has 84 players, how many are not seniors.
zaharov [31]

There are 60 players on football team that are not seniors.

Step-by-step explanation:

<u>Method 1:</u>

Given

Total students = 84

Also given that

2 out of 7 are seniors

Which is 2/7

So in order to find the total number of seniors we will multiply the whole number of students to 2/7

Senior\ students = \frac{2}{7} * 84\\= 24

So there are 24 seniors on the football team.

Players that are not seniors = 84 - 24 = 60

There are 60 players who are not seniors.

<u>Method 2:</u>

We can divide the total number by 7, to get how many sets of 7 players will be there

= 84/7 = 12

Now,

Multiplying 12 with 2 will give us the number of seniors in football team.

12*2 = 24 seniors

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Not seniors =84-24 = 60

Keywords: Percentage, Units

Learn more about percentage at:

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7 0
3 years ago
WILL MARK BRAINLIEST! PLEASE HELP!<br> Write 206 in base 7
Anna71 [15]

Answer:

413_7

Step-by-step explanation:

Convert the following to base 7:

206_10

Hint: | Starting with zero, raise 7 to increasingly larger integer powers until the result exceeds 206.

Determine the powers of 7 that will be used as the places of the digits in the base-7 representation of 206:

Power | \!\(\*SuperscriptBox[\(Base\), \(Power\)]\) | Place value

3 | 7^3 | 343

2 | 7^2 | 49

1 | 7^1 | 7

0 | 7^0 | 1

Hint: | The powers of 7 (in ascending order) are associated with the places from right to left.

Label each place of the base-7 representation of 206 with the appropriate power of 7:

Place | | | 7^2 | 7^1 | 7^0 |  

| | | ↓ | ↓ | ↓ |  

206_10 | = | ( | __ | __ | __ | )_(_7)

Hint: | Divide 206 by 7 and find the remainder. The remainder is the first digit from the right.

Determine the value of the first digit from the right of 206 in base 7:

206/7=29 with remainder 3

Place | | | 7^2 | 7^1 | 7^0 |  

| | | ↓ | ↓ | ↓ |  

206_10 | = | ( | __ | __ | 3 | )_(_7)

Hint: | Divide the whole number part of the previous quotient, 29, by 7 and find the remainder. The remainder is the next digit.

Determine the value of the next digit from the right of 206 in base 7:

29/7=4 with remainder 1

Place | | | 7^2 | 7^1 | 7^0 |  

| | | ↓ | ↓ | ↓ |  

206_10 | = | ( | __ | 1 | 3 | )_(_7)

Hint: | Divide the whole number part of the previous quotient, 4, by 7 and find the remainder. The remainder is the last digit.

Determine the value of the last remaining digit of 206 in base 7:

4/7=0 with remainder 4

Place | | | 7^2 | 7^1 | 7^0 |  

| | | ↓ | ↓ | ↓ |  

206_10 | = | ( | 4 | 1 | 3 | )_(_7)

Hint: | Express 206_10 in base 7.

The number 206_10 is equivalent to 413_7 in base 7.

Answer: 206_10 =413_7

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