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3 years ago

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What did Charles Darwin learn from reading the work of Charles Lyell? O Earth is relatively young. All geological change is caus

ed by living organisms O Earth is very old. The processes that formed old rocks on Earth do not operate today.

1 answer:

AnnyKZ [126]3 years ago

6 0

Earth is relatively young

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Which factors can have the greatest effect on the health of a river

Tomtit [17]

It’s the letter C.................

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3 years ago

A scientist randomly mutates the DNA of a bacterium. She then sequences the bacterium’s daughter cells, and finds that the daugh

valentina_108 [34]

Your answer will be DNA Pol 1.

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3 years ago

small group of 100 people decide to isolate themselves from the world and move to a small and remote deserted island. Out of thi

irina [24]

Answer:

Frequency of p $= 0.684$

Frequency of p $= 0.316$

Number of individuals with homozygous dominant (AA) $= 47$

Number of individuals with heterozygous (Aa) $= 43$

Number of individuals with homozygous recessive (aa) $= 10$

Explanation:

Out of 100 people, 10 have albino skin (aa)

So, the frequency of homozygous recessive individuals $(q^{2})$ is $\frac{10}{100} = 0.1$

Now, q will be

$= \sqrt{q^{2} } = \sqrt{0.1} \\= 0.316$

As per Hardy Weinberg's equation -

$p + q = 1$

Substituting the value of q in above equation, we get -

$p + 0.316 = 1p = 1 -0.316\\p = 0.684$

Now the frequency of homozygous dominant (AA) will be

$p^{2} = 0.684^{2} \\= 0.467$

Hence, out of 100 people $0.467 * 100 = 46.7 or 47$ people are homozygous dominant (AA)

Like wise out of 100 people $0.1 * 100 = 10$ people are homozygous recessive (aa)

As per As per Hardy Weinberg's equation-

$p^{2} + q^{2} + 2pq = 1\\$

Substituting the values in above equation, we get -

$0.467 + 0.316 + 2pq = 1\\2pq = 1 -( 0.467+ 0.1)\\2pq = 0.433$

So, out of 100 people $0.433 * 100 = 43.3 or 43$ people are heterozygous (Aa)

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4 years ago

Stacy bought two vegetables one of them is scaly with a few buds and the other has hairy structures which parts of the vegetable

Vilka [71]

This is from another brainly answer it's the same questions but it should be the correct answer because it's a certified answer. Hope this helps!

Tuber is thick underground stem, such as potato for example. It usually has buds from which new plants could grow. So, the first part of Stacy's vegetable is definitely turbous stem. The other part must be root, because it has hairy structures. These hair-like structures have function in <span>the absorption of water and minerals from the soil.</span>

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3 years ago

Read 2 more answers

To study the fate of carbon during glycolysis under aerobic conditions, cultured cells are fed with 14C-glucose labeled in vario

kondor19780726 [428]

Answer:

D. The methyl group of acetyl CoA becomes radio-labeled

Explanation:

During the steps in glycolysis, the carbon at position 1, becomes C-1 in dihydroxyacetone phosphate during the cleavage of fructose-1,6-bisphosphate to dihydroxyacetone phosphate and glyceraldehyde-3-phosphate. Subsequently on isomerization of dihydroxyacetone phosphate to glyceraldehyde-3-phosphate, C-1 of dihydroxyacetone phosphate becomes C-3 of glyceraldehyde-3-phosphate.

Furthermore, in pyruvate, the end product of glycolysis, C-3 is converted to a methyl group which then becomes the methyl group in the acetyl-CoA molecule produced from the oxidative decarboxylation of pyruvate.

Since the radioactive 14-C of radio-labeled glucose occupies position 1, it will become the methyl group of acetyl-CoA.

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3 years ago