Given:

howler monkey: {15, 16, 17, 17, 17, 17, 18, 19}
spider monkey: {12, 13, 13, 14, 14, 14, 16, 16}

The mean of the first set (howler monkey) = (15 + 16 + 17 + 17 + 17 +17 + 18 + 19)/ 8
The sum of all weights is divided by the number of monkeys weighed (n = 8)

mean = 17

Do the same for the second set (spider monkey) = 12+ 13 + 13+ 14 + 14+ 14 +14 +16 + 16 / 8

mean = 15.75

The ratio of the two is 17:15.75 or 1.08 is to 1.

3 0

3 years ago

A map has a scale of 1 in : 3 km. If the actual distance is 15 km, what is the distance on the map?

Black_prince [1.1K]

Answer:

5 in.

Step-by-step explanation:

The ratio of map distance to real distance is 1 in : 3 km meaning that 1 inch on the map describes 15 km in real life.

15 km is 5 times 3 km, so the map distance is 5 times 1 in., or 5 in.

1 in. x 5 : 3 km x 5

This is a "school math" problem where things come out nicely! Another way to look at this is with equivalent fractions.

$\frac{\text{1 in}}{\text{5 km}} = \frac{\text{m}}{\text{15 km}}$

"cross multiply"

$5m = (15)(1)\\5m=15\\m=3 \text{ in.}$

4 0

2 years ago

The picture up there need this for today!!

tatyana61 [14]

Answer:

I believe its 30 different ways.

Step-by-step explanation:

Each different topping can be added times. so 5 times 6 is 30.

3 0

3 years ago