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2 years ago

12

A giant scoop, operated by a crane, is in the shape of a hemisphere of radius 21 inches. The scoop is used to transfer molten st

eel into a cylindrical storage tank with diameter 28 inches. If the scoop is filled to the top, what will be the height of the molten steel in the storage tank?
Write the answer as a decimal, rounded to the nearest tenth.

1 answer:

eduard2 years ago

3 0

Answer:

31.5 in

Step-by-step explanation:

Volume of a hemisphere = (2/3) $\pi$ r³
(where r is the radius)
Volume of a cylinder = $\pi$ r²h
(where r is the radius and h is the height)
radius r = (1/2) diameter

First, find the volume of the scoop using the volume of a hemisphere formula with r = 21:

Volume = (2/3) $\pi$ x 21³ = 6174 $\pi$ in³

Now equate the found volume of the scoop to the equation of the volume of a cylinder with r = 14, and solve for h:

$\pi$ 14²h = 6174 $\pi$

196 $\pi$ h = 6174 $\pi$

Divide both sides by $\pi$ : 196h = 6174

Divide both sides by 196: h = 31.5

Therefore, the height of the molten steel in the storage tank is 31.5 in

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sesenic [268]

Hey you!

If I understood your question correctly, here's your answer:

0.93/3 = 0.31

0.31 × 4 = 1.24

So, it would cost $1.24 for 4 packs.

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3 years ago

A coin is tossed and a number cube is rolled. What is the probability that the coin shows heads and the number cube shows 5? a.

Inessa [10]

Answer:

1/12

Step-by-step explanation:

P( coin = heads) = number of heads / total = 1/2

P( cube = 5) = number of 5's / total =1/6

P( heads, 5) =1/2 * 1/6 = 1/12

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3 years ago

Read 2 more answers

If Anna have 8000 and gave jim 300 and bought some items a shoes for 290 a suit for 400 and a phone for 2000

vovangra [49]

Answer: Assuming the unit is dollars, the answer would be $5,010.

Explanation:

Step 1: 8000-300 is 7700.

Step 2: 7700-290 is 7410

Step 3: 7410-400 is 7010

Step 4: 7010-2000 is 5010

So, the answer is Anna has $5,010 dollars left after giving Jim $300, buying shoes for $290, a suit for $400 and spending $2,000 dollars on a new phone.

6 0

3 years ago

A bag contains two six-sided dice: one red, one green. The red die has faces numbered 1, 2, 3, 4, 5, and 6. The green die has fa

gayaneshka [121]

Answer:

the probability the die chosen was green is 0.9

Step-by-step explanation:

Given that:

A bag contains two six-sided dice: one red, one green.

The red die has faces numbered 1, 2, 3, 4, 5, and 6.

The green die has faces numbered 1, 2, 3, 4, 4, and 4.

From above, the probability of obtaining 4 in a single throw of a fair die is:

P (4 | red dice) = $\dfrac{1}{6}$

P (4 | green dice) = $\dfrac{3}{6}$ = $\dfrac{1}{2}$

A die is selected at random and rolled four times.

As the die is selected randomly; the probability of the first die must be equal to the probability of the second die = $\dfrac{1}{2}$

The probability of two 1's and two 4's in the first dice can be calculated as:

= $\begin {pmatrix} \left \begin{array}{c}4\\2\\ \end{array} \right \end {pmatrix} \times \begin {pmatrix} \dfrac{1}{6} \end {pmatrix} ^4$

= $\dfrac{4!}{2!(4-2)!} ( \dfrac{1}{6})^4$

= $\dfrac{4!}{2!(2)!} \times ( \dfrac{1}{6})^4$

= $6 \times ( \dfrac{1}{6})^4$

= $(\dfrac{1}{6})^3$

= $\dfrac{1}{216}$

The probability of two 1's and two 4's in the second dice can be calculated as:

= $\begin {pmatrix} \left \begin{array}{c}4\\2\\ \end{array} \right \end {pmatrix} \times \begin {pmatrix} \dfrac{1}{6} \end {pmatrix} ^2 \times \begin {pmatrix} \dfrac{3}{6} \end {pmatrix} ^2$

= $\dfrac{4!}{2!(2)!} \times ( \dfrac{1}{6})^2 \times ( \dfrac{3}{6})^2$

= $6 \times ( \dfrac{1}{6})^2 \times ( \dfrac{3}{6})^2$

= $( \dfrac{1}{6}) \times ( \dfrac{3}{6})^2$

= $\dfrac{9}{216}$

∴

The probability of two 1's and two 4's in both dies = P( two 1s and two 4s | first dice ) P( first dice ) + P( two 1s and two 4s | second dice ) P( second dice )

The probability of two 1's and two 4's in both die = $\dfrac{1}{216} \times \dfrac{1}{2} + \dfrac{9}{216} \times \dfrac{1}{2}$

The probability of two 1's and two 4's in both die = $\dfrac{1}{432} + \dfrac{1}{48}$

The probability of two 1's and two 4's in both die = $\dfrac{5}{216}$

By applying Bayes Theorem; the probability that the die was green can be calculated as:

P(second die (green) | two 1's and two 4's ) = The probability of two 1's and two 4's | second dice)P (second die) ÷ P(two 1's and two 4's in both die)

P(second die (green) | two 1's and two 4's ) = $\dfrac{\dfrac{1}{2} \times \dfrac{9}{216}}{\dfrac{5}{216}}$

P(second die (green) | two 1's and two 4's ) = $\dfrac{0.5 \times 0.04166666667}{0.02314814815}$

P(second die (green) | two 1's and two 4's ) = 0.9

Thus; the probability the die chosen was green is 0.9

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3 years ago

For what value of x would the expression below be undefined? 6x − 9 x − 5

Marina86 [1]

6x - 9x - 5 =

combine like terms

6 - 9 = - 3

- 3x - 5 =

leave x by itself

- 3x - 5 =
+3x
___
0
- 5 = 3x

solve for x (division)

- 5 = 3x
___
3
-5/3 = x OR x = -5/3

3 0

3 years ago