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1 year ago

How does accenture generate value for clients through agile and devops?

1 answer:

4 0

Through quicker time to market, better quality products, and higher customer satisfaction Agile and DevOps are key components of Accenture's value creation for clients.

Accenture plc is a Dublin-based, Irish-American professional services firm with a focus on information technology (IT) services and consulting. It was listed on the Fortune Global 500 and recorded $61.6 billion in revenue in 2022. 91 of the Fortune Global 100 and more than 75 percent of the Fortune Global 500 are among Accenture's current clients.

When General Electric wanted to install a computer at Appliance Park in Louisville, Kentucky, in the early 1950s, Accenture conducted a feasibility study for the company. This study led to GE installing a UNIVAC I computer and printer, which is thought to be the first commercial use of a computer in the United States. A post was held by Joseph Glickauf, a pioneer in computer consulting.

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a company is using aws fargate to run a batch job whenever an object is uploaded to an amazon s3 bucket. the minimum ecs task co

wlad13 [49]

The suitable option to implement with the LEAST amount of effort is

Set up a CloudWatch Event rule to detect S3 object PUT operations and set the target to the ECS cluster with the increased number of tasks. Create another rule to detect S3 DELETE operations and set the target to the ECS Cluster with 1 as the Task count.

<h3>What are Amazon S3 buckets?</h3>

A bucket is know to be a kind of a cup or a container that is known to be made for objects saved in Amazon S3.

Note that based on the above firm's work, The suitable option to implement with the LEAST amount of effort is

Set up a CloudWatch Event rule to detect S3 object PUT operations and set the target to the ECS cluster with the increased number of tasks. Create another rule to detect S3 DELETE operations and set the target to the ECS Cluster with 1 as the Task count.

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See question below

An application is hosted in an AWS Fargate cluster that runs a batch job whenever an object is loaded on an Amazon S3 bucket. The minimum number of ECS Tasks is initially set to 1 to save on costs, and it will only increase the task count based on the new objects uploaded on the S3 bucket. Once processing is done, the bucket becomes empty and the ECS Task count should be back to 1.

Which is the most suitable option to implement with the LEAST amount of effort?

Set up a CloudWatch Event rule to detect S3 object PUT operations and set the target to a Lambda function that will run Amazon ECS API command to increase the number of tasks on ECS. Create another rule to detect S3 DELETE operations and run the Lambda function to reduce the number of ECS tasks.

Set up a CloudWatch Event rule to detect S3 object PUT operations and set the target to the ECS cluster with the increased number of tasks. Create another rule to detect S3 DELETE operations and set the target to the ECS Cluster with 1 as the Task count.

Set up an alarm in CloudWatch to monitor CloudTrail since the S3 object-level operations are recorded on CloudTrail. Create two Lambda functions for increasing/decreasing the ECS task count. Set these as respective targets for the CloudWatch Alarm depending on the S3 event.

Set up an alarm in CloudWatch to monitor CloudTrail since this S3 object-level operations are recorded on CloudTrail. Set two alarm actions to update ECS task count to scale-out/scale-in depending on the S3 event.

3 0

1 year ago

All of the following are simple steps for optimizing web page content except:

dangina [55]

Answer:

The correct answer is letter "B": segmenting computer servers to perform dedicated functions.

Explanation:

Computer segmentation refers to separating a server from the rest of the computers within the same network. The segmentation can separate one computer from others or groups of servers from one another. Thew type of segmentation will always depend on the device used to do the separation of the servers.

3 0

3 years ago

Write programs for two MSP430 boards to do the following:

Rainbow [258]

Answer:

Explanation:

#include "msp430g2553.h"

#define TXLED BIT0

#define RXLED BIT6

#define TXD BIT2

#define RXD BIT1

const char string[] = { "Hello World\r\n" };

unsigned int i; //Counter

int main(void)

{

WDTCTL = WDTPW + WDTHOLD; // Stop WDT

DCOCTL = 0; // Select lowest DCOx and MODx settings

BCSCTL1 = CALBC1_1MHZ; // Set DCO

DCOCTL = CALDCO_1MHZ;

P2DIR |= 0xFF; // All P2.x outputs

P2OUT &= 0x00; // All P2.x reset

P1SEL |= RXD + TXD ; // P1.1 = RXD, P1.2=TXD

P1SEL2 |= RXD + TXD ; // P1.1 = RXD, P1.2=TXD

P1DIR |= RXLED + TXLED;

P1OUT &= 0x00;

UCA0CTL1 |= UCSSEL_2; // SMCLK

UCA0BR0 = 0x08; // 1MHz 115200

UCA0BR1 = 0x00; // 1MHz 115200

UCA0MCTL = UCBRS2 + UCBRS0; // Modulation UCBRSx = 5

UCA0CTL1 &= ~UCSWRST; // **Initialize USCI state machine**

UC0IE |= UCA0RXIE; // Enable USCI_A0 RX interrupt

__bis_SR_register(CPUOFF + GIE); // Enter LPM0 w/ int until Byte RXed

while (1)

{ }

}

#pragma vector=USCIAB0TX_VECTOR

__interrupt void USCI0TX_ISR(void)

{

P1OUT |= TXLED;

UCA0TXBUF = string[i++]; // TX next character

if (i == sizeof string - 1) // TX over?

UC0IE &= ~UCA0TXIE; // Disable USCI_A0 TX interrupt

P1OUT &= ~TXLED; }

#pragma vector=USCIAB0RX_VECTOR

__interrupt void USCI0RX_ISR(void)

{

P1OUT |= RXLED;

if (UCA0RXBUF == 'a') // 'a' received?

{

i = 0;

UC0IE |= UCA0TXIE; // Enable USCI_A0 TX interrupt

UCA0TXBUF = string[i++];

}

P1OUT &= ~RXLED;

}

7 0

4 years ago

Write the definition of a function named quadratic that receives three double parameters a, b, c. If the value of a is 0 then th

VMariaS [17]

Answer:

#include <iostream>

#include <cmath>

using namespace std;

//initialize function quadratic

void quadratic(double, double, double);

int main() {

//declare double variables a, b and c

double a,b,c;

//take input from user

cin>>a>>b>>c;

//call function quadratic

quadratic(a,b,c);

return 0;

}

void quadratic(double a, double b, double c){

double root,n;

//check if variable a is equal to zero

if(a==0){

cout<<"no solution for a=0"<<endl;

return;

}

//check if b squared - 4ac is less than zero

else

if(((b*b)-(4*a*c))<0){

cout<<"no real solutions"<<endl;

return;

}

//print the largest root if the above conditions are not satisfied

else{

n=((b*b)-(4*a*c));

root=(-b + sqrt(n)) / (2*a);

cout<<"Largest root is:"<<root<<endl;

}

return ;

}

Explanation:

Read three double variables a, b and c from the user and pass it to the function quadratic. Check if the value of variable a is equal to zero. If true, print "no solution for a=0". If this condition is false, check if b squared - 4ac is less than zero. If true, print "no real solutions". If this condition is also false, calculate the largest solution using the following formula:

largest root = (-b + square root of (b squared - 4ac)) / (2*a)

Input 1:

2 5 3

Output 2:

Largest root is:-1

Input 2:

5 6 1

Output 2:

Largest root is:-0.2

5 0

4 years ago

Which quality determines an individual's ability to be open to changes and complete tasks in an ever-changing work environment?

MrMuchimi

Answer

Flexibility

Explanation:

8 0

3 years ago