Plugging the values if x and y the last option is correct
3x-y=4
Answer:
<em>x = 1 + ( √ 10 )/ 2, or x = 1 - ( √ 10 )/ 2; Option A</em>
Step-by-step explanation:
See steps below;
I would prefer answering this question by completing the square, rather than applying a quadratic formula;
3x^2 - 6x - 12 = 0, ⇒ Add 12 to either side,
3x^2 - 6x = 12, ⇒ Divide either side by 3,
x^2 - 2x = 4, ⇒ Write the equation in the form x^2 + 2ax + a^2 = (x + a)^2,
x^2 - 2ax + a^2 = 4 + a^2, ⇒ Solve for a
2ax = -2x,
a = - 1, ⇒ Substitute value of a,
x^2 - 2x + 1 = 4 + 1,
( x - 1 )^2 = 5, ⇒ Solve for x,
x = √5 + 1, and x = - √5 + 1,
In other words; <em>Solution : x = 1 + ( √ 10 )/ 2, or x = 1 - ( √ 10 )/ 2; Option A</em>
9514 1404 393
Answer:
(c) 11
Step-by-step explanation:
As x goes up by 1, f(x) goes up by 2. The next line of the chart would be ...
x = 4+1 = 5; f(x) = 9+2 = 11
The appropriate choice is f(5) = 11.
Answer:
follow step by step to get answer
Step-by-step explanation:
take 40 and multiply it by 0.08 then add that number to 40 and you get your answer.
Yes, the statement is true since they are both prime :)
