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Karo-lina-s [1.5K]
3 years ago
8

!! PLEASE HELP, TIMED!!Multiple choice, BRAINLIEST for correct answer

Mathematics
1 answer:
ipn [44]3 years ago
3 0
The third answer is the correct answer
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Fractions: three oil tankers together contain 37 5/7 litres of oil. If two tankers have 11 3/14 litres and 12 3/7 litres of oil.
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Step-by-step explanation:

It is given that, three oil tankers together contain 37 5/7 litres of oil.

Total volume of oil is \dfrac{264}{7}\ L

If two tankers have 11 3/14 litres and 12 3/7 litres of oil.

Oil in first tanker is \dfrac{157}{14}\ L

Oil in second tanker is \dfrac{87}{7}\ L

Oil in first and second tanker is :

\dfrac{157}{14}\ L+\dfrac{87}{7}\ L=\dfrac{331}{14}\ L

Noo, oil in the third tanker = total volume - (Oil in first tanker + second tanker )

=\dfrac{264}{7}\ L-\dfrac{331}{14}\ L\\\\=\dfrac{197}{14}\ L

Hence, this is the required solution.

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Multiplying exponents adds the exponent, meaning that inside of the brackets, it is a^4 * b^5. Multiply the exponents by two because you are squaring the entire equation. Therefore, m=8 and n=10

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