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Andrew [12]
3 years ago
11

What percent of 12 is 9? A. 25% B. 67% C. 75% D. 108% E. 133%

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
6 0

Answer:

75%

Step-by-step explanation:

75% = 3/4

3/4 * 12 = 9

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54/52 is the answer or you could reduce it to 27/26
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A police officer claims that the proportion of accidents that occur in the daytime (versus nighttime) at a certain intersection
Roman55 [17]

Answer: -1.78

Step-by-step explanation:

As per given description, we have

Population proportion : p=0.35

Sample size : n= 500

Sample proportion : \hat{p}=\dfrac{156}{500}=0.312

Test statistic for population proportion :-

z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}\\\\\\=\dfrac{0.312-0.35}{\sqrt{\dfrac{0.35(1-0.35)}{500}}}\\\\=-1.78146747757\ \ \text{(Simplified)}\\\\\approx-1.78

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3 0
3 years ago
>
kondor19780726 [428]

Answer:

23 degrees

Step-by-step explanation:

Find the diagram attached

The sum of angle on the straight line is 180°

103+3x+15+x+10 = 180

128+4x =180

4x = 180-128

4x = 52

x = 52/4

x = 13

The measure of the angle of the intersection between Derby Drive and Rosemont is x+10

= 13+10

= 23 degrees

Hence the measure of the angle is 23 degrees

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3 years ago
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Uh I’m not even gonna question it but thanks for the free points ig? Lol
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the pitch, or frequency, of a vibrating string varies directly with the square root of the tension. if a string vibrates at a fr
Naily [24]
\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad  y=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad  variation
\end{array}\\\\
-------------------------------\\\\
\begin{array}{llll}
\stackrel{frequency}{f}\textit{ of a vibrating string varies directly}\\
\qquad \qquad \textit{with the square root of the tension }\stackrel{tension}{t}
\end{array}

\bf f=k\sqrt{t}\quad \textit{we also know that }
\begin{cases}
f=300\\
t=8
\end{cases}\implies 300=k\sqrt{8}
\\\\\\
\cfrac{300}{\sqrt{8}}=k\implies \cfrac{300}{\sqrt{2^2\cdot 2}}=k\implies \cfrac{300}{2\sqrt{2}}=k\implies \cfrac{150}{\sqrt{2}}=k
\\\\\\
\textit{and we can \underline{rationalize} it to }\cfrac{150\sqrt{2}}{2}\implies 75\sqrt{2}=k

\bf thus\qquad f=\stackrel{k}{75\sqrt{2}}\sqrt{t}\implies \boxed{f=75\sqrt{2t}}\\\\
-------------------------------\\\\
\textit{now, when t = 72, what is \underline{f}?}\qquad f=75\sqrt{2(72)}
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3 years ago
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