Answer:
Answer is
Step-by-step explanation:
Given that there are two urns. First urn contains 3 white balls and 6 yellow balls and the second urn contains 7 white balls and 3 yellow balls.
A ball is drawn from each urn.
Probability for ball from urn I is white = no of white balls/total balls in I urn
Probability for ball from urn II is white = no of white balls/total balls in I urn
Since drawing one ball from each urn is independent of the other we find
Prob that both balls are white=
Prob that ball from I urn is white *Prob that ball from II urn is white
=
To solve this we use the
equation,
<span> M1V1 = M2V2</span>
<span> where M1 is the
concentration of the stock solution, V1 is the volume of the stock solution, M2
is the concentration of the new solution and V2 is its volume.</span>
<span>
</span>
<span>M1 = .80 g H2SO4 / g solution (1018 g solution / L solution ) (1 mol / 98.08) = 8.30 M</span>
<span>
</span>
<span>8.30 (V1) = (5.0 M) (1.5 L)</span>
<span>V1 = 0.9036 L or 903.6 mL of the stock needed</span>
24/72 which simplifies to 12/36 which then simplifies to 6/18 which then also simplifies to 3/9 then also simplifies to 1/3.
Answer:
1 55
2 130
3 15
Step-by-step explanation:
