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WITCHER [35]
3 years ago
9

The graph of h(x) = (x - 3)2 is a translation of the

Mathematics
1 answer:
Allushta [10]3 years ago
5 0

Answer:

right by 3 I think

Step-by-step explanation:

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8
diamong [38]

Answer:

b i think

Step-by-step explanation:

6 0
3 years ago
I need to know how to do it in Distributive Property.
kotykmax [81]
A(b-c)=ab-ac

(1/7)(1/3h-1/2)=(1/7)(1/3h)-(1/7)(1/2)=1/21h-1/14

now we gots
6 and 1/7+1/21h-1/14
rearange
6 and 1/7-1/14+1/21h
make common denom which is 14
6 and 2/14-1/14+1/21h
6 and 1/14+1/21h

6 0
3 years ago
Ashley correctly answered 85% of the questions She had on her last math test if she missed six problems how many questions were
vovikov84 [41]
Do 6÷0.15 and you get 40. Please give Brainliest I am so close to the next level.
3 0
3 years ago
Which value for the constant ccc makes w=5w=5w, equals, 5 an extraneous solution in the following equation? \sqrt{29+4w}=23-cw 2
miv72 [106K]

Answer:

c=6

Step-by-step explanation:

In order to solve the original equation, we would have to square both sides of the equation:

\begin{aligned}\sqrt{29+4w}&=23-cw\\\\ \left(\sqrt{29+4w}\right)^2&=(23-cw)^2\\\\ 29+4w&=(23-cw)^2\end{aligned}  

29+4w

​  

 

(  

29+4w

​  

)  

2

 

29+4w

​  

 

=23−cw

=(23−cw)  

2

 

=(23−cw)  

2

 

​  

 

However, squaring both sides of an equation can create extraneous solutions! [Why?]

Hint #22 / 4

Let's plug \blueD w=\blueD{5}w=5start color #11accd, w, end color #11accd, equals, start color #11accd, 5, end color #11accd into the last equation we obtained:

\begin{aligned}29+4\blueD w&=(23-c\blueD{w})^2\\\\ 29+4(\blueD 5)&=(23-c(\blueD{5}))^2\\\\ 49&=(23-5c)^2\end{aligned}  

29+4w

29+4(5)

49

​  

 

=(23−cw)  

2

 

=(23−c(5))  

2

 

=(23−5c)  

2

 

​  

 

This equation is correct, both when 23-5c=723−5c=723, minus, 5, c, equals, 7 and when 23-5c=-723−5c=−723, minus, 5, c, equals, minus, 7.

However, the original equation is not correct for 23-5c=-723−5c=−723, minus, 5, c, equals, minus, 7, since this way we obtain \sqrt{49}=-7  

49

​  

=−7square root of, 49, end square root, equals, minus, 7.

Hint #33 / 4

Therefore, an extraneous solution is obtained for the ccc-value that makes 23-5c23−5c23, minus, 5, c equal -7−7minus, 7, which is c=6c=6c, equals, 6.

Substituting this back into the original equation gives \sqrt{29+4w}=23-6w  

29+4w

​  

=23−6wsquare root of, 29, plus, 4, w, end square root, equals, 23, minus, 6, w. You can now solve this for www and see for yourselves that w=5w=5w, equals, 5 is indeed extraneous.

Hint #44 / 4

The answer is:

c=6c=6

4 0
3 years ago
A cone has a base radius of length r, and an perpendicular height length h. If the height remains the same, and the radius is mu
sergij07 [2.7K]

The formula for the volume of a cone is:

V= (1/3) x \pi x r^{2} x height

Since this is a quadratic equation, if the radius is multiplied by 3, then the volume is multiplied by its square, which is 9.


Hope this helps!

7 0
3 years ago
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