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serg [7]
4 years ago
9

1. Find the magnitude and direction angle for the vector v = 5cos144°i + 5sin144°j.

Mathematics
1 answer:
o-na [289]4 years ago
5 0
1. B
2. D
3. C
4. B
5. B
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5*10^5 is how many times bigger that 1*10^5
weqwewe [10]

Answer:

5

Step-by-step explanation:

5*10^5=500000 and 1*10^5=100000

6 0
3 years ago
An ice cream parlor sells milkshakes in various sizes:
Harlamova29_29 [7]
No it is not a linear equation...in order for it to be linear it must be a straight line, but this line is curved slightly which prevents the pattern from being linear
7 0
3 years ago
1/2a+ -7 + 1/2a = 1/3<br><br>what is the value of a
Olin [163]
1/2a - 7 + 1/2a = 1/3
1/2a + 1/2a = 1/3 + 7
2/2a = (1 + 21)/3
a = 22/3
5 0
3 years ago
Read 2 more answers
Nadia is a stockbroker. She earns 11% commission each week. Last week, she sold 7,200 worth of stocks. How much did she make las
elena55 [62]

Answer:

She made 792 dollars that week. I'm assuming it is just asking for the yearly commission she made. That would be 41,184 dollars a year.

Step-by-step explanation:

7200 x 0.11 = 792 Weekly

52 Weeks in a year

792 x 52 = 41184 Yearly (if that's what it's asking for)

6 0
3 years ago
Find each measurement indicated round your answers to the nearest tenth. Part 1d. NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW
valkas [14]

Answer:

see explanation

Step-by-step explanation:

Using the Sine rule in all 3 questions

(1)

\frac{a}{sinA} = \frac{b}{sinB} , substitute values , firstly calculating ∠ B

[ ∠ B = 180° - (78 + 49)° = 180° - 127° = 53° ]

\frac{a}{sin78} = \frac{18}{sin53} ( cross- multiply )

a sin53° = 18 sin78° ( divide both sides by sin53° )

a = \frac{18sin78}{sin53} ≈ 22.0 ( to the nearest tenth )

(3)

\frac{c}{sinC} = \frac{a}{sinA} , substitute values

\frac{35}{sinC} = \frac{45}{sin134} ( cross- multiply )

45 sinC = 35 sin134° ( divide both sides by 35 )

sinC = \frac{35sin134}{45} , then

∠ C = sin^{-1} ( \frac{35sin134}{45} ) ≈ 34.0° ( to the nearest tenth )

(5)

Calculate the measure of ∠ B

∠ B = 180° - (38 + 92)° = 180° - 130° = 50°

\frac{a}{sinA} = \frac{b}{sinB} , substitute values

\frac{BC}{sin38} = \frac{10}{sin50} ( cross- multiply )

BC sin50° = 10 sin38° ( divide both sides by sin50° )

BC = \frac{10sin38}{sin50} ≈ 8.0 ( to the nearest tenth )

3 0
3 years ago
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